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yuradex [85]
3 years ago
10

A 50-kilogram student threw a 0.40-kilogram ball with a speed of 20 meters per second. What was the magnitude of the impulse tha

t the student exerted the ball?
Physics
1 answer:
Sveta_85 [38]3 years ago
6 0
By definition, the magnitude of the impulse is given by
 I = delta P
 where,
 delta P = variation of the linear amount of movement.
 P = m * v
 We have then:
 I = delta P
 I = delta m * v
 I = (0.40) * (20) - (0.40) * (0)
 I = 8 Kg * m / s
 answer:
 the magnitude of the impulse that the student exerted the ball was
 I = 8 Kg * m / s
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