Question

To withstand ‘g-forces’ of up to 10 g’s, caused by suddenly pulling out of a steep dive, fighter jet pilots train on a ‘human centrifuge.’ If the length of the centrifuge arm is 12 m, at what speed is the rider moving when she experiences 10 g’s?

Answer 1

Answer:

34.292 m/s

Explanation:

When plane dives the gravitational acceleration becomes 10 times extra i-e

acceleration a = g= 10g's=10 ×9.8= 98 m/sec2

radius of dive circle = 12 m

v= speed= ?

Using

$a= \frac{v^{2} }{r}$

==> $v^{2}$ = a × r = 98 × 12 = 1176 $(\frac{m}{s}) ^{2}$

==> v= $\sqrt{1176(\frac{m}{s} )^{2} }$

==> v= 34.292 m/s