A network ____ usually contains a computer, networked peripheral, or network device.

What is the value of count after this nested FOR loop executes fully.

Alisiya [41]

Answer:

168 (although the =< must be corrected to <=)

Explanation:

int count = 0;

for (int row = 4; row <= 15; row++)

for (int col = 0; col < 13; col = col +2)

count+=2;

The inner for loop runs 7 times (for col = 0,2,4,6,8,10,12). Anything higher is not less than 13. Therefore the inner loop increments count by 2 seven times, i.e. it increments count by 14.

The outer for loop runs 12 times (for row = 4,5,6,7,8,9,10,11,12,13,14,15).

If the count is incremented by 14 twelve times, you are incrementing it by 14*12 = 168.

Therefore the count goes from 0 to 168 after the nested loops.

5 0

3 years ago

Question 9/10

Firlakuza [10]

They sometimes offer free service

5 0

3 years ago

Read 2 more answers

ShellShock had the potential for an unauthorized user to gain access to a server. It affected many internet-facing services, whi

mina [271]

Answer: Windows

Explanation:

ShellShock: Also called Bashdoor, it is a security bug which is found in the Bash shell of operating system e.g. Unix. It allows the hacker to execute scripts and commands by gaining unauthorized access. This affects many machines, devices that use Bash. Servers like web servers are most affected as most of them run Unix based OS like OS X. Most vulnerable are those who use Unix or Linux operating systems.

Microsoft Windows does not use Bash so it does not directly affect Windows os. For those who are using Windows PC, Windows phones and websites that are developed by MS software are non-vulnerable to ShellShock.

4 0

3 years ago

Write a program FindDuplicate.java that reads n integer arguments from the command line into an integer array of length n, where

kozerog [31]

Answer:

public class FindDuplicate{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int n = 5;
int arr[] = new int[n];
for(int i=0; i < arr.length; i++){
int inputNum = input.nextInt();
if(inputNum >=1 && inputNum <=n) {
arr[i] = inputNum;
}
}
for(int j =0; j < arr.length; j++){
for(int k = 0; k < arr.length; k++){
if(j == k){
continue;
}else{
if(arr[j] == arr[k]){
System.out.println("True");
return;
}
}
}
}
System.out.println("False");
}
}

Explanation:

Firstly, create a Scanner object to get user input (Line 4).

Next, create an array with n-size (Line 7) and then create a for-loop to get user repeatedly enter an integer and assign the input value to the array (Line 9 - 14).

Next, create a double layer for-loop to check the each element in the array against the other elements to see if there is any duplication detected and display "True" (Line 21 - 22). If duplication is found the program will display True and terminate the whole program using return (Line 23). The condition set in Line 18 is to ensure the comparison is not between the same element.

If all the elements in the array are unique the if block (Line 21 - 23) won't run and it will proceed to Line 28 to display message "False".

7 0

3 years ago

Write a python program to print the following series 3..10..31..94......n<br><br>Pls answer fast..

butalik [34]

I've included my code in the picture below. Best of luck

8 0

3 years ago