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2 years ago

12

Evaluate the expression: 2x + 5 for x = 3

1 answer:

lubasha [3.4K]2 years ago

5 0

Substitute the value of the variable into the equation and simplify.
11
11

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2x+2y=8 in function form step by step please?

nasty-shy [4]

You could get two different functions out of this:

<u>2x + 2y = 8</u>

1). <u> 'y' as a function of 'x'</u>

Subtract 2x from each side: 2y = -2x + 8

Divide each side by 2 : <em> y = -x + 4</em>

2). <u> 'x' as a function of 'y' :</u>

Subtract 2y from each side: 2x = -2y + 8

Divide each side by 2 : <em> x = -y + 4</em>

Those two functions look the same, but that's just because the original
equation given in the problem was so symmetrical. In general, they're
not the same function.

7 0

2 years ago

Read 2 more answers

Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a

Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force ( $\vec F$ ), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

$\vec F = \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right)$ (1)

Vector (ordered pair - polar form)

$\vec F = \left(\|\vec F\|, \theta\right)$

Sum of vectorial components (linear combination)

$\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j}$ (2)

Where:

$\|\vec F\|$ - Norm of the vector force, in newtons.

$\theta$ - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

$\hat{i}$ , $\hat{j}$ - Orthogonal axes, no unit.

If we know that $\|\vec F\| = 30\,lbf$ and $\theta = 25^{\circ}$ , then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

$\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]$

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]$

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

8 0

2 years ago

Jane read 3/8 of a book for 6 days. How many books did she read?

otez555 [7]

$Hey$ $there!$

$The$ $answer$ $to$ $your$ $question$ $is$ $2 \frac{1}{4}$ $books$ .

$To$ $solve$ $this$ , $we$ $must$ $multiply$ $\frac{3}{8}$ $by$ $6$

$\frac{3}{8} *\frac{6}{1}=\frac{18}{8} =2\frac{1}{4}$

$Hope$ $it$ $helps!$ $Have$ $a$ $great$ $day!$

7 0

3 years ago

70°<br> 13<br> ४<br> c=<br> 12.2<br> x<br> A

Aleonysh [2.5K]

Answer:

sin70=13/x

$\sin(70) \times x = 13$

$x = 13 \times \sin(70)$

$x = 13 \div 0.9397$

13.8

6 0

2 years ago

Sidana [21]

Answer:

- 0.83

Step-by-step explanation:

just add the recurring bar on top of the 3 and it should be correct

6 0

1 year ago