Please help;-; tysm! (23 points)

Which equation represents the vertical asymptote of the graph?

Annette [7]

The curve is y equals 0 from negative x to negative y near x equals negative 8.

If a curve has Vertical Asymptote i.e the line x=p,it is never touched by the given curve.The curve remains almost parallel to the line x=p, till the end.The two i.e a line and curve will never meet each other.

→ x is almost equal to p but not p.

so in the denominator , it is x=-8,

Vertical Asymptote occurs when we put , denominator of curve=0.

so vertical asymptote of curve is : x= -8

8 0

3 years ago

Please helppppppp ❤️

liberstina [14]

Answer:

Inverse of f exists.

Step-by-step explanation:

From the graph attached,

If we do the horizontal line test for the function graphed,

We find the function as one to one function.

In other words for every input value (x-value) there is a different output value.

Since, for one-to-one functions, inverse of the functions exist.

Therefore, the answer will be,

The inverse of 'f' exists.

7 0

3 years ago

What is the approximate distance between points A and B?

Aleks04 [339]

Answer:

$\displaystyle d \approx 7.62$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra II

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Find points from graph.

Point A(1, 4)

Point B(-2, -3)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Substitute in points [DF]: $\displaystyle d = \sqrt{(-2-1)^2+(-3-4)^2}$
(Parenthesis) Subtract: $\displaystyle d = \sqrt{(-3)^2+(-7)^2}$
[√Radical] Exponents: $\displaystyle d = \sqrt{9+49}$
[√Radical] Add: $\displaystyle d = \sqrt{58}$
[√Radical] Evaluate: $d = 7.61577$
Round: $\displaystyle d \approx 7.62$

3 0

3 years ago

(6e−3f−4)⋅2= otay otay

Dmitry [639]

Answer:

Step-by-step explanation:

if you need to evaluate the expression:

multiply 2 with the parenthesis

12e-6f-8

8 0

3 years ago

Read 2 more answers

Construct ∆ABC using the following segment

salantis [7]

Answer:

Use the angle copy procedure to copy the angles to the ends of c.

Step-by-step explanation:

An angle is copied with a straightedge two settings of a compass.

Set the compass to an arbitrary radius. An appropriate choice is a radius that is half or more of the length of the shortest ray of the angles you want to copy.
Put the point of the compass at the vertex of an angle you want to copy. Using that same radius, draw arcs through both rays of the angle. Do this for all the angles you want to copy.
Put the point of the compass at the place where you want the vertex of the copied angle. Here, that is either (both) end points of segment c. (You might want to label the ends of segment c as "A" and "B" so you know which angle you're copying where.) Using the same radius as before, draw an arc through the segment and through the space where you expect the ray from the copied angle to lie.
For one of the source angles, set the compass radius to the distance between the points where the first arc crosses the angle's rays. Then, put the point of the compass at the place on the segment c where the corresponding arc crosses. Use the compass to mark a point on that arc the same distance as on the source angle. Draw a line from the vertex through the point you just marked. That line will make the same angle with c as the original angle.
Repeat step 4 for the other angle you want to copy, at the other end of segment c. In general, the compass setting will be different (unless all the angles have the same measure).

The place where the rays from the copied angles cross is the third vertex (vertex C) of the triangle you're constructing.

_____

Comments on the attached diagram

In the attached diagram, "step 1" is to place the target vertex. You already have that as one end of segment C. The arcs numbered 2 and 3 in the diagram are the arcs resulting from executing steps 2 and 3 above. (They have arbitrary radius "r", which is the same everywhere.) You will have two sets, because you are copying two angles.

The arcs numbered 4 and 5 in the diagram have radius ST, the distance you set in step 4 above. That distance is used as the radius of arc 5, so the length VW will be the same as the length ST. The straightedge is used to draw a line through B and W, completing the copy of the angle.

6 0

3 years ago