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Agata [3.3K]
3 years ago
12

if esther deposited $50 at the end of each month into an account with no interest, how much money would she have saved by the en

d of 12 months?​
Mathematics
2 answers:
MAVERICK [17]3 years ago
7 0

Answer:

By the end of 12 months, Esther would have $600.

Step-by-step explanation:

As Esther deposits $50 each month in her account, and the account does not produce interests, it is just an addition of money each time she puts $50 in it. That money won't increase until she puts another $50 at the end of the following month. Therefore, by the end of twelve months, she would have $600 (50 x 12 = 600).

Crazy boy [7]3 years ago
4 0

Answer:

$600

Step-by-step explanation 50 dollars every month for 12 months you would do 12 *50 and it gives you 600

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2 years ago
Two isosceles triangles have the same base length. the legs of one of the triangles are twice as long as the legs of the other.
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An isosceles triangle is a type of triangle where 2 sides are equal.

Picture out 2 triangles with the same base length. 
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To put it into variables, let:
     B = the same base length of the two triangles
     A = the length of one leg the smaller triangle
    2A = the length of one leg of the bigger triangle

Given:    Perimeter of smaller triangle = 23cm
              Perimeter of bigger triangle = 43cm

Recall the formula for solving the perimeter of a triangle:
      Perimeter = A + B + C
   
where, A, B, and C are the legs of the triangle

Since the triangle involved is an isosceles triangle, therefore, we can say that
        Perimeter = 2A + B     ,   2 legs are equal ( A=C )

Substituting the given perimeter value to the formula. 
   
23cm = 2A + B                    ⇒   equation 1  (smaller triangle)
43cm = 2(2A) + B                ⇒   equation 2  (bigger triangle)

Simplifying equation 2.
                                    43cm = 4A + B
  (rearranging)             B = 43cm - 4A        ⇒ equation 3

Substituting equation 3 to equation 1:
   (equation 1)              23cm = 2A + B
                                    23cm = 2A + (43cm - 4A)
                                    23cm = -2A + 43cm
                                    2A = 43cm - 23cm
                                    2A = 20cm  ⇒   length of the leg of the bigger triangle
                                     A = 10cm   ⇒   length of the leg of the smaller triangle

To solve for the base length, just substitute the value of A to equation 3
     (equation 3)       B = 43cm - 4A
                               B = 43cm - 4(10cm)
                               B = 3 cm

Final Answer:

• For the smaller triangle, the length of the sides are 10cm, 10cm, and 3cm
• For the bigger triangle, the length of the sides are 20cm, 20cm, and 3cm
8 0
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