Answer:
0.014767
Step-by-step explanation:
Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
Answer:
x =√[y²+(27)²] = √[ z² - 3² +(27)²]
Step-by-step explanation:
step 1) x=√[y²+(27)²]
step 2)
We find y
z²=y²+3² → y² = z² - 3²
step 3) x = √[ z² - 3² +(27)²]
The ratio is 1:3 because every 3 people 1 is a vegetarian
