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3 years ago

Helppppppppppppp plssssssssssss

Mathematics

1 answer:

ozzi3 years ago

4 0

Answer:

Derrick mistakenly combined the numbers adding it together but the numbers are not the same value to be combined. You cannot add yards and ft together.

Width = 55ft

Area = 4950 sq ft

Cost = $9900

Step-by-step explanation:

Derrick mistakenly combined the numbers adding it together but the numbers are not the same value to be combined. You cannot add yards and ft together.

You have to convert the yards to ft to add it to the other ft.

1 Yard = 3 ft

So the width is 18 yards 1 ft = 54ft + 1ft = 55ft

To calculate the area is L x W

The length is 30 yards. Convert that to ft = 90ft

So 90 x 55 = 4950 sq ft

At $2 per sq ft, you multiply the 4950 sq ft by $2

2 x 4950 = $9900

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Answer:

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Step-by-step explanation:

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3 years ago

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Ilia_Sergeevich [38]

Answer:

a) $\bf 0.3446^{25}=2.7095*10^{-12}$

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Step-by-step explanation:

Since 4300/25 = 172, in average every single person should weight 172 pounds to exceed the design limit.

The probability that one person weights 172 pounds or more is the area under the Normal curve with mean 160 pounds and standard deviation 30 pounds to the right of 172.

In Excel and OpenOffice Calc, this value is found with the formula

=1-NORMDIST(172;160;30;1)

(NORMDIST(172;160;30;1) gives the area to the left of 172, so 1-NORMDIST(172;160;30;1) gives the area to the right of 172)

and equals 0.3446

(see picture 1)

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$\bf 0.3446^{25}=2.7095*10^{-12}$

Similarly, we must find a weight w such that if p is the area to the left of w, then

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$\bf p=\sqrt[25]{0.0001}=0.6918$

w would be the point such that the area under the Normal curve with mean 160 pounds and standard deviation 30 pounds to the right of w equals 0.6918.

In Excel and OpenOffice Calc this is found with

=NORMINV(1-0.6918;160;30)

and equals 144.97 pounds

(See picture 2)

and the design limit that is exceeded by 25 occupants with probability 0.0001 is 25*144.97 = 3,624.25 pounds

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