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3 years ago

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ozzi3 years ago

4 0

Answer:

Derrick mistakenly combined the numbers adding it together but the numbers are not the same value to be combined. You cannot add yards and ft together.

Width = 55ft

Area = 4950 sq ft

Cost = $9900

Step-by-step explanation:

Derrick mistakenly combined the numbers adding it together but the numbers are not the same value to be combined. You cannot add yards and ft together.

You have to convert the yards to ft to add it to the other ft.

1 Yard = 3 ft

So the width is 18 yards 1 ft = 54ft + 1ft = 55ft

To calculate the area is L x W

The length is 30 yards. Convert that to ft = 90ft

So 90 x 55 = 4950 sq ft

At $2 per sq ft, you multiply the 4950 sq ft by $2

2 x 4950 = $9900

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Conner and Jana are multiplying (3⁵6⁸)(3⁹6¹⁰).

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<h3>Conner work is correct. Jana work is wrong</h3>

<em><u>Solution:</u></em>

<em><u>Given that,</u></em>

<em><u>Conner and Jana are multiplying:</u></em>

$(3^56^8)(3^96^{10})$

Given Conner's work is:

$(3^56^8)(3^96^{10}) = 3^{5+9}6^{8+10} = 3^{14}6^{18}$

We have to check if this work is correct

Yes, Conner work is correct

From given,

$(3^56^8)(3^96^{10})\\\\3^5 \times 6^8 \times 3^9 \times 6^{10}$

Use the following law of exponent

$a^m \times a^n = a^{m+n}$

Therefore,

$3^5 \times 6^8 \times 3^9 \times 6^{10} = 3^5 \times 3^9 \times 6^8 \times 6^{10} = 3^{5+9} \times 6^{8+10} = 3^{14} \times 6^{18}$

<em><u>Given Jana's work is:</u></em>

$(3^56^8)(3^96^{10}) = 3^{5.9}6^{8.10} = 3^{45}6^{80}$

This is incorrect

The powers of same base has to be added. But here, powers are multiplied which is wrong

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Step-by-step explanation:

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One-half m minus three-fourths n equals 16, when n equals 8?

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Hey!

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Expression:

0.5m - 0.75n = 16 (1/2m - 3/4n = 16)

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Solution:

0.5m - 0.75n = 16

0.5m - 0.75(8) = 16

0.5m - 6 = 16

0.5m - 6 + 6 = 16 + 6

0.5m = 22

0.5m/0.5 = 22/0.5

m = 44

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Answer:

$\boxed{ \bf m~=~44}$

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Hope This Helped! Good Luck!

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