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MissTica
3 years ago
5

(Angles in

Mathematics
1 answer:
Bingel [31]3 years ago
4 0

Answer:

m<ABC = 116°

m<CDE = 67°

Step-by-step explanation:

✔️m<ABC = 180 - m<BAD (adjacent angles of a parallelogram are supplementary)

m<ABC = 180 - 64° (Substitution)

m<ABC = 116°

✔️m<CDA = m<CDE + m<ADE (angle addition postulate)

m<CDA = m<CDE + 49°

m<CDA = m<ABC (opposite angles of a parallelogram are congruent)

m<CDE + 49° = 116° (substitution)

m<CDE = 116° - 49° (Substraction property of equality)

m<CDE = 67°

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r-ruslan [8.4K]
-5 + x/22 = -1

+ 5 for both side

x
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multiply by 4

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x = 88
5 0
3 years ago
Which is the area of triangle LMN? Group of answer choices 24 square units 27 square units 54 square units 48 square units
irina [24]

Answer:

√65/2 square units

Step-by-step explanation:

Find the diagram attached

Area of the triangle = 1/2 * base * height

To get the base and height, we will use the distance formula;

Area of the triangle LMN = 1/2 * LM * MN

For MN

Given the coordinate M(3, 2) and N(1, 3)

MN = √(3-2)²+(1-3)²

MN = √1²+(-2)²

MN = √1+4

MN = √5

For LM;

Given the coordinate L(1, -1) and M(3, 2)

LM = √(2-(-1))²+(3-1)²

LM = √(2+1)²+(2)²

LM = √3²+(2)²

LM = √9+4

LM = √13

Area of the triangle LMN = 1/2 * √13 * √5

Area of the triangle LMN = √65/2 square units

4 0
3 years ago
Use the elimination method to sole the system of equations. choose the correct ordered pair.
Crank
(X,Y) = (4,0)


That’s what I got.
8 0
3 years ago
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A parking lot in the shape of a trapezoid has an area of 12052.1 square meters. The length of one base is 82.4 meters, and the l
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Can someone help me solve the inequality-2x+4&gt;8 with the steps? Thanks
stellarik [79]

\huge\text{Hey there!}

\rm{-2x + 4 > 8}

\large\textsf{SUBTRACT  4 to BOTH SIDES}

\rm{-2x + 4 - 4 > 8 - 4}

\large\textsf{CANCEL puts 4 - 4 because that gives you 0}

\large\textsf{KEEP: 8 - 4 because that helps solve for the x-value}

\rm{8 - 4 = \boxed{\bf 4}}

\rm{NEW\  EQUATION: -2x > 4}

\large\textsf{DIVIDE -2 to BOTH SIDES}

\mathsf{\dfrac{-2}{-2}>\dfrac{4}{-2}}

\mathsf{CANCEL\  out: \dfrac{-2}{-2}\  because\  that\  gives\  you\  1}

\mathsf{KEEP: \dfrac{4}{-2} \ because \ it \ helps \you \ compare\  to \  the \ x-value }

\mathsf{\dfrac{4}{-2} = \boxed{\bf -2}}

\rm{\bold{x < -2 }}

\rm{It\ is \ an\  O PENED \ circle \  shaded \  to \ the \ left \ side \ of \ the \ number  \ line}

\boxed{\boxed{\large\textsf{Answer: } \mathsf{\bf x < -2}}}\huge\checkmark

\large\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

8 0
3 years ago
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