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VMariaS [17]
3 years ago
6

Could u guys try this one out as well

Mathematics
1 answer:
Korolek [52]3 years ago
3 0

Answer:

D) a reflection over the line x = 0 followed by a reflection over the line y = 0.

Step-by-step explanation:

In this problem, the original figure is in quadrant I (1) and the second image is in quadrant III (3).  In order for the figure to make this transition and be 'flipped' into the opposite direction of the original figure, a reflection would have to take place.  If triangle 'A' is reflected over the line y = x or y = -x, the orientation of the triangle would stay the same, meaning the point of the triangle would still face upward.  If you reflect over the line x = 0 and then again over the line x = 0 (as in C), your triangle would be in the same spot.  However, if you reflect triangle 'A' over x = 0, you would get a 'flipped image' into quadrant 4 and the orientation of the triangle would face downward.  Following this reflection by another reflection over the line y=0 would give you the mirror image in quadrant III (3).  So, D is the correct sequence of reflections.  

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3 years ago
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Por favor responder a esta pregunta
ahrayia [7]
Por determinante:
5...1...1
1...0...1 = 0 --> se o determinante for igual a 0, os pontos estarão alinhados.
3...3...1

calculando: (5 x 0 x 1 + 1 x 1 x 3 + 1 x 3 x 1) - (1 x 0 x 3 + 1 x 1 x 1 + 3 x 1 x 5) = 
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3 years ago
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for significance level
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    (x₁ - x₂) ± tα/2,v₁ * \sqrt{ \frac{s_1^2 }{n_1} + \frac{s_2^2}{n_2} }
   ........1

where v(degree of fredom)=(s₁²/n₁+s₂²/n₂)² / ((s₁²/n₁)²/n₁-1)+(s₂²/n₂)²/n₂-1))
    by putting values 
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From Statistics table,
      See the t table at α/2=0.05  and v=3.81026
use interpolation as v value is not in the table,
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(60.666-58.333) ± (2.853)*\sqrt{ \frac{35.005^2 }{3} + \frac{43.924^2}{3} }      

  2.333 ± 92.516 is the correct answer.


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