Question

Could u guys try this one out as well

Answer 1

Answer:

D) a reflection over the line x = 0 followed by a reflection over the line y = 0.

Step-by-step explanation:

In this problem, the original figure is in quadrant I (1) and the second image is in quadrant III (3).  In order for the figure to make this transition and be 'flipped' into the opposite direction of the original figure, a reflection would have to take place.  If triangle 'A' is reflected over the line y = x or y = -x, the orientation of the triangle would stay the same, meaning the point of the triangle would still face upward.  If you reflect over the line x = 0 and then again over the line x = 0 (as in C), your triangle would be in the same spot.  However, if you reflect triangle 'A' over x = 0, you would get a 'flipped image' into quadrant 4 and the orientation of the triangle would face downward.  Following this reflection by another reflection over the line y=0 would give you the mirror image in quadrant III (3).  So, D is the correct sequence of reflections.