What's an equivalent expression to 4(c+9)
1 answer:
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Answer:
1,805 kg.
Step-by-step explanation:
We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.
First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.
Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.
Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.
For this case, the first thing we must do is find the scale factor.
For this, we use one of the dimensions. We will use the width of the photo.
We have then:
Then, we look for the value of the height of the new photo. To do this, we multiply the scale factor by the original dimension.
We have then:
Answer:
the new height will be:
d.168 inches