Hi there!
We are told to write an equation of a line in standard form with a slope for 3 that goes through the point (9,-4). There are many ways to do this, but the easiest one would be using the point-slope form. This is the point-slope form:

If we let m = 3, y1 = -4, x1 = 9, we can substitute the values back into the equation to get:

. We can simplify the equation to get

. Now, we combine like terms by subtracting 4 from both sides, giving us y = 3x - 31. Finally, we subtract 3x from both sides to get -3x + y = -31. Therefore, the answer to your query is
-3x + y = -31.
Solution:
we are given that
Clayton needs to reflect the triangle below across the line y=x.
And as we know the reflection of the point (x,y) across the line y = x is the point (y, x).
Hence the new Traingle will be on the other side of the line y=x and position of x and y-coordinates of the vertices of the trangle gets interchanged.
Hence the Options that applies are:
C’ will move because all points move in a reflection.
The image and the pre-image will be congruent triangles. (Because reflection just changes the position of the trinagle not the property)
The image and pre-image will not have the same orientation because reflections flip figures.
What is the question you are asking?
39/89 because of sohcahtoa