Answer:
Section A = 25,000 seats
Section B = 14,600 seats
Section C = 10,400 seats
Step-by-step explanation:
Total Seats = 50,000
Seats in Section A cost = $30
Seats in Section B cost = $24
Seats in Section C cost = $18
Total sales from the event = $1,287,600
No. of Seats in section A = No. seats in Section B + No. seats in Section C
A = B + C
or, 2A = 50,000
A = 25,000 seats @ $30/seat = $750,000
B + C = 25,000
24B + 18C = 537,600
24B + 18(25,000 - B) = 537,600
24B + 450,000 - 18B = 537,600
6B = 87600
B = 14,600
C = 10,400
Hence;
A = 25,000 seats
B = 14,600 seats
C = 10,400 seats
a) Volume of Rectangular prism is 
b) Volume of cube is 
c) Volume of cube is 
d) Volume of Rectangular prism is 
Step-by-step explanation:
Part a)
Volume of rectangular prism with
length= 
width= 
height = 
The formula used to find Volume of rectangular prism is:

Putting values:

So, Volume of Rectangular prism is 
Part b)
Volume of cube with side length of 
The formula used to find Volume of cube is:

Putting value of length and finding volume:

So, Volume of cube is 
Part c)
Volume of cube with side length of 
The formula used to find Volume of cube is:

Putting value of length and finding volume:

So, Volume of cube is 
Part d)
Volume of rectangular prism with
length= 
width= 
height = 
The formula used to find Volume of rectangular prism is:

Putting values:

So, Volume of Rectangular prism is 
Keywords: Volume
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Answer:
a) 0.82
b) 0.18
Step-by-step explanation:
We are given that
P(F)=0.69
P(R)=0.42
P(F and R)=0.29.
a)
P(course has a final exam or a research paper)=P(F or R)=?
P(F or R)=P(F)+P(R)- P(F and R)
P(F or R)=0.69+0.42-0.29
P(F or R)=1.11-0.29
P(F or R)=0.82.
Thus, the the probability that a course has a final exam or a research paper is 0.82.
b)
P( NEITHER of two requirements)=P(F' and R')=?
According to De Morgan's law
P(A' and B')=[P(A or B)]'
P(A' and B')=1-P(A or B)
P(A' and B')=1-0.82
P(A' and B')=0.18
Thus, the probability that a course has NEITHER of these two requirements is 0.18.
Answer:
corresponding angles
the angles are equal
equation: 9x+8 = 4x+18
x=2
angle measurements: 26⁰
Step-by-step explanation:
solve your equation
9x+8 = 4x+18
subtract 4x from each side
5x + 8 = 18
subtract 8 from each side
5x = 10
divide by 5
x = 2
insert x=2 into original equations to make sure you get the same answer.
9(2) + 8 = 26
4(2) + 18 = 26