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Anna007 [38]
3 years ago
10

Please help me! Anything is appreciated!

Mathematics
1 answer:
Mila [183]3 years ago
7 0
B,D,G,H are right angles
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Andy has 901 cards for a big game if he gives away 789 how much does he have left
Leokris [45]

Answer:

the answer is 112

Step-by-step explanation:

901-789=112

4 0
3 years ago
Four less than the product of ten and a number is eleven. is
nikitadnepr [17]

Answer:

If written in algebraic form it is, 10x - 4 = 11

Step-by-step explanation:

Four less ( minus 4 ) than the product of ten and a number ( 10 times x ) is eleven ( equal to 11 ).

Hopefully this helps!

Brainliest please?

3 0
3 years ago
in the given kite SZ= 10yards , WZ = 10 yards TZ=12 yards , and RZ=32 yards Determine the area of the kite
Fynjy0 [20]

If we assume the given segments are those from the vertices to the point of intersection of the diagonals, it seems one diagonal (SW) is 20 yards long and the other (TR) is 44 yards long. The area (A) of the kite is half the product of the diagonals:

... A = (1/2)·SW·TR = (1/2)·(20 yd)·(44 yd)

... A = 440 yd²

5 0
3 years ago
How do I find the missing side lengths? Someone please help!!!
adell [148]
45°-45°-90°
Hope I could help!

3 0
3 years ago
At a raffle, 1500 tickets are sold at $2 each. There are four prizes given for $500, $250, $150, and $75. You buy one ticket. Us
wolverine [178]

Answer:

<u>The expected value of every ticket is a loss of $ 1.35</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Number of tickets sold at the raffle = 1,500

Price of each ticket = $ 2

Total prizes = 1 * $ 500 + 1 * $ 250 + 1 * $ 150 + 1 * $ 75

2. Use a probability distribution table to calculate the expected value of your gain. Your expected value is_____ ?

Let's answer the question using a probability distribution for the gains, this way:

  • Probability of 1st prize of $ 498 (500 - ticket) = 1/1,500
  • Probability of 2nd prize of $ 248 (250 - ticket) = 1/1,500
  • Probability of 3rd prize of $ 148 (150 - ticket) = 1/1,500
  • Probability of 4th prize of $ 73 (75 - ticket) = 1/1,500
  • Probability of losing $ 2 (ticket) = 1,496/1,500

Now, we calculate the mean for all the tickets (winners and non-winners), this way:

Expected value = [(1,496 * -2) + (1 * 498) + (1 * 248) + ( 1 * 148) + ( 1 * 73)]/1,500

Expected value = [- 2,992 +498 + 248 + 148 + 73)/1,500

Expected value = -2,025/1,500 = - 1,35

<u>The expected value of every ticket is a loss of $ 1.35</u>

8 0
4 years ago
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