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svetoff [14.1K]

3 years ago

6

-8y-2(5y+9) can yall help me!!!!!!!!!!!! it is 10 points

1 answer:

My name is Ann [436]3 years ago

5 0

Answer:

-18y - 18

Step-by-step explanation:

The -2 needs to be distributed into both values in the parenthesis. This will make the equation -8y - 10y - 18. Then, you put the like terms together. This will result in the final equation, -18y - 18

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The radius of a right circular cone is 2 in. By what factor will the volume change if the radius of the cone is multiplied by 3

Vinil7 [7]

The volume of a right
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factor of 25. If the height
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7 0

3 years ago

Verify that the following function is a probability mass function, and determine the requested probabilities.

kirill115 [55]

Answer:

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Step-by-step explanation:

5 0

3 years ago

Which shows the expressions rewritten with the least common denominator? 5x+3/3x and 7x/2x^2

andrey2020 [161]

Answer:

$\frac{10x^2+6x}{6x^2}$ and $\frac{21x}{6x^2}$ .

Step-by-step explanation:

The given expression is:

$\frac{5x+3}{3x}$ and $\frac{7x}{3x^2}$ .

The least common denominator is: $6x^2$ .

We collect LCM for the denominator to obtain;

$\frac{2x(5x+3)}{6x^2}$ and $\frac{3(7x)}{6x^2}$ .

We multiply out the parenthesis to obtain;

$\frac{10x^2+6x}{6x^2}$ and $\frac{21x}{6x^2}$ .

Therefore the correct answer is B or the second option.

4 0

3 years ago

Find the general solution of<br><br> dz/dt=5ze^(sint)cost+2e^(sint)cost

gizmo_the_mogwai [7]

Answer:

The general solution of given differential equation is $\frac{1}{5}ln|5z+2|=e^{\sin t}+C$ .

Step-by-step explanation:

The given differential equation is

$\frac{dz}{dt}=5ze^{\sin t}\cos t+2e^{\sin t}\cos t$

Taking out common factors.

$\frac{dz}{dt}=(5z+2)e^{\sin t}\cos t$

Using variable separable method, we get

$\frac{dz}{5z+2}=e^{\sin t}\cos t dt$

Integrate both sides.

$\int\frac{dz}{5z+2}=\int e^{\sin t}\cos t dt$

$I_1=I_2$ .... (1)

First solve LHS,

$I_1=\int\frac{dz}{5z+2}$

Substitute $5z+2=u$

$5\frac{dz}{du}=1$

$dz=\frac{1}{5}du$

$I_1=\frac{1}{5}\int\frac{du}{u}$

$I_1=\frac{1}{5}ln|u|+C_1$

$I_1=\frac{1}{5}ln|5z+2|+C_1$

Now, solve RHS,

$I_2=\int e^{\sin t}\cos t dt$

Substitute $\sin t=v$ ,

$\cos t\frac{dt}{dv}=1$

$\cos tdt=dv$

$I_2=\int e^{v}dv$

$I_2=e^{v}+C_2$

$I_2=e^{\sin t}+C_2$

Subtitle the values of I₁ and I₂ in equation (1).

$\frac{1}{5}ln|5z+2|+C_1=e^{\sin t}+C_2$

$\frac{1}{5}ln|5z+2|=e^{\sin t}+C_2-C_1$

$\frac{1}{5}ln|5z+2|=e^{\sin t}+C$

Therefore the general solution of given differential equation is $\frac{1}{5}ln|5z+2|=e^{\sin t}+C$ .

4 0

3 years ago

One week, Madeline earned $61.20 at'her job when she worked for 4 hours. If she is

zheka24 [161]

Answer:

16 Hours

Step-by-step explanation:

She would need to work 16 hours because 61.20 x 4 = 244.80. And 61.20 x 3 = 183.60. Correct me if I'm wrong, Thank You!

7 0

3 years ago

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