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3 years ago

Write the fraction 6/6 as a sum of fractions three different ways

Mathematics

2 answers:

Mila [183]3 years ago

8 0

1
3/3
420/420 this is my answer but there is probably more ways

sammy [17]3 years ago

5 0

1, 3/3, 420/420 why such a wierd qustion

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The stock market gained 45 points on Tuesday and lost 32 points on Wednesday. It had closed on Monday at 2760 points. Where did

Svetllana [295]

Answer:

The market closed with a rating of 2773 points on Wednesday.

Step-by-step explanation:

Lets start with what we know:

Monday at close it had a rating of 2760 points.

Tuesday it gained 45 points.

Wednesday it had lost 32 points.

Once written out it becomes less intimidating to answer.

Monday + Tuesday + Wednesday = Answer

2760 + 45 - 32

= 2805 - 32

= 2773

7 0

2 years ago

Read 2 more answers

Factorise 12x - 30 help me please

Sonbull [250]

Answer:

6(2x-5) when factored

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

What is the answer for number 7?

aivan3 [116]

Answer:

Step-by-step explanation:

x=30

m=abe=180

8 0

3 years ago

Calculate the perimeter of the following shape. 6cm y= 10 cm 12 cm 5 cm

Phantasy [73]

Answer:

The perimeter is the length of the outline of a shape. To find the perimeter of a rectangle or square you have to add the lengths of all the four sides.

10 cm + 12 cm + 5 cm + 6 cm

= 33 cm

3 0

3 years ago

Use the Fundamental Theorem of Calculus to find the area of the region between the graph of the function x5 + 8x4 + 2x2 + 5x + 1

belka [17]

Answer:

The area of the region between the graph of the given function and the x-axis = 25,351 units²

Step-by-step explanation:

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15

If 'f' is a continuous on [a ,b] then the function

$F(x) = \int\limits^a_b {f(x)} \, dx$

By using integration formula

$\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c$

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

$\int\limits^6_^-6} (x^{5} + 8 x^{4} + 2 x^{2} + 5 x + 15) )dx$

On integration , we get

= $(\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}$

$F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)$

= $(\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))$