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postnew [5]
3 years ago
15

Let event Aequalssubject is telling the truth and event Bequalspolygraph test indicates that the subject is lying. Use your own

words to translate the notation Upper P (B|A )into a verbal statement. Choose the correct option below. A. The probability that the polygraph indicates lying given that the subject is actually lying. B. The probability that the polygraph indicates truthfulness given that the subject is actually telling the truth. C. The probability that the polygraph indicates lying given that the subject is actually telling the truth. D. The probability that the polygraph indicates truthfulness given that the subject is actually lying.
Mathematics
1 answer:
pochemuha3 years ago
3 0

Answer:

C is the right answer

Step-by-step explanation:

In this case we have the events

<em>A: The subject is telling the truth. </em>

<em>B: The the polygraph indicates that the subject is lying </em>

Recall that P(B|A) is defined as the probability that the event B occurs given that the event has already occurred, and is equals to P(B∩A)/P(A).

So, with the events we have defined, <em>P(B|A) indicates the probability that the polygraph indicates lying given that the subject is actually telling the truth. </em>

The most suitable answer is thus, C

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Suppose that $1800 is borrowed for three years at an interest rate of 2% per year, compounded continuously. Find the amount owed
Schach [20]

1908

Step-by-step explanation:2% of 1800 is 36 36 x 3 is 108 + 1800 =1908

5 0
2 years ago
BRAINIEST AND 10 POINTS
Alinara [238K]

Answer:

Last answer is correct..

7 0
3 years ago
In the radius of a circle with an area of 10 inches squared is reduced by half what is the area of the new circle
Sphinxa [80]

Answer:

Hence when the radius is halved the area is divided by 4

2.5 inches^2

Step-by-step explanation:

Given data

Area= 10inches^2

We know that the expression for the area of  a circle is given as

Area= πr^2

10= 3.142*r^2

10/3.142= r^2

r^2= 3.18

Square both sides

r= √3.18

r= 1.78 inches

Now let us half the radius and find the area of the new circle

r/2= 1.78/2

r= 0.89

Area of the new circle is

Area= 3.142*0.89^2

Area= 3.142*0.7921

Area= 2.5 inches^2

7 0
3 years ago
If <img src="https://tex.z-dn.net/?f=x%20%3D%209%20-%204%5Csqrt%7B5%7D" id="TexFormula1" title="x = 9 - 4\sqrt{5}" alt="x = 9 -
Komok [63]

Observe that

\left(\sqrt x - \dfrac1{\sqrt x}\right)^2 = \left(\sqrt x\right)^2 - 2\sqrt x\dfrac1{\sqrt x} + \left(\dfrac1{\sqrt x}\right)^2 = x - 2 + \dfrac1x

Now,

x = 9 - 4\sqrt5 \implies \dfrac1x = \dfrac1{9-4\sqrt5} = \dfrac{9 + 4\sqrt5}{9^2 - \left(4\sqrt5\right)^2} = 9 + 4\sqrt5

so that

\left(\sqrt x - \dfrac1{\sqrt x}\right)^2 = (9 - 4\sqrt5) - 2 + (9 + 4\sqrt5) = 16

\implies \sqrt x - \dfrac1{\sqrt x} = \pm\sqrt{16} = \pm 4

To decide which is the correct value, we need to examine the sign of \sqrt x - \frac1{\sqrt x}. It evaluates to 0 if

\sqrt x = \dfrac1{\sqrt x} \implies x = 1

We have

9 - 4\sqrt5 = \sqrt{81} - \sqrt{16\cdot5} = \sqrt{81} - \sqrt{80} > 0

Also,

\sqrt{81} - \sqrt{64} = 9 - 8 = 1

and \sqrt x increases as x increases, which means

0 < 9 - 4\sqrt5 < 1

Therefore for all 0 < x < 1,

\sqrt x - \dfrac1{\sqrt x} < 0

For example, when x=\frac14, we get

\sqrt{\dfrac14} - \dfrac1{\sqrt{\frac14}} = \dfrac1{\sqrt4} - \sqrt4 = \dfrac12 - 2 = -\dfrac32 < 0

Then the target expression has a negative sign at the given value of x :

x = 9-4\sqrt5 \implies \sqrt x - \dfrac1{\sqrt x} = \boxed{-4}

Alternatively, we can try simplifying \sqrt x by denesting the radical. Let a,b,c be non-zero integers (c>0) such that

\sqrt{9 - 4\sqrt5} = a + b\sqrt c

Note that the left side must be positive.

Taking squares on both sides gives

9 - 4\sqrt5 = a^2 + 2ab\sqrt c + b^2c

Let c=5 and ab=-2. Then

a^2+5b^2=9 \implies a^2 + 5\left(-\dfrac2a\right)^2 = 9 \\\\ \implies a^2 + \dfrac{20}{a^2} = 9 \\\\ \implies a^4 + 20 = 9a^2 \\\\ \implies a^4 - 9a^2 + 20 = 0 \\\\ \implies (a^2 - 4) (a^2 - 5) = 0 \\\\ \implies a^2 = 4 \text{ or } a^2 = 5

a^2 = 4 \implies 5b^2 = 5 \implies b^2 = 1

a^2 = 5 \implies 5b^2 = 4 \implies b^2 = \dfrac45

Only the first case leads to integer coefficients. Since ab=-2, one of a or b must be negative. We have

a^2 = 4 \implies a = 2 \text{ or } a = -2

Now if a=2, then b=-1, and

\sqrt{9 - 4\sqrt5} = 2 - \sqrt5

However, \sqrt5 > \sqrt4 = 2, so 2-\sqrt5 is negative, so we don't want this.

Instead, if a=-2, then b=1, and thus

\sqrt{9 - 4\sqrt5} = -2 + \sqrt5

Then our target expression evaluates to

\sqrt x - \dfrac1{\sqrt x} = -2 + \sqrt5 - \dfrac1{-2 + \sqrt5} \\\\ ~~~~~~~~~~~~ = -2 + \sqrt5 - \dfrac{-2 - \sqrt5}{(-2)^2 - \left(\sqrt5\right)^2} \\\\ ~~~~~~~~~~~~ = -2 + \sqrt5 + \dfrac{2 + \sqrt5}{4 - 5} \\\\ ~~~~~~~~~~~~ = -2 + \sqrt5 - (2 + \sqrt5) = \boxed{-4}

5 0
2 years ago
beth sold half of her comic books and then bought nine more. shoe now has 28. with how much did she begin?
tekilochka [14]

Answer:

<h2><em>38</em></h2>

Step-by-step explanation:

I believe the answer would be 38 i'm not 100% sure but here is why i think so. If Beth sold half of her comic books and then bought nine more that would mean ahe had 19 before she bought the other 9 so 19x2 which is 38 so she began with 38 then sold half which is 19 and then bought 9 more to now have 28.

6 0
3 years ago
Read 2 more answers
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