Answer
I believe it is 195
Step-by-step explanation:
1 9 and 5 are odd 1+9 is 10
and 195 is less than 200
Answer:
b
Step-by-step explanation:
Answer:
Step-by-step explanation:
#1 Number of ways picking 2 from 6 = 6C2 = 15
#2 Arranging them in a circle (consider 1 pair AB)
can be done
1,5 (ABBBBB) or (5,1)
2,4 ( AABBBB) or (4,2)
3,3
1,1 (ABABAB)
all up = 7 ways
#3 = product of #1 and #2 = 15x7 = 105
Given expression is
![\sqrt[4]{\frac{16x^{11}y^8}{81x^7y^6}}](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B%5Cfrac%7B16x%5E%7B11%7Dy%5E8%7D%7B81x%5E7y%5E6%7D%7D)
Radical is fourth root
first we simplify the terms inside the radical


So the expression becomes
![\sqrt[4]{\frac{16x^4y^2}{81}}](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B%5Cfrac%7B16x%5E4y%5E2%7D%7B81%7D%7D)
Now we take fourth root
![\sqrt[4]{16} = 2](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16%7D%20%3D%202)
![\sqrt[4]{81} = 3](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B81%7D%20%3D%203)
![\sqrt[4]{x^4} = x](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%5E4%7D%20%3D%20x)
We cannot simplify fourth root (y^2)
After simplification , expression becomes
![\frac{2x\sqrt[4]{y^2}}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B2x%5Csqrt%5B4%5D%7By%5E2%7D%7D%7B3%7D)
Answer is option B
The answer is -6+x=8. x is the unknown number. To find the distance, try to use a number line. And the answer to the expression is 14. To get from -6 to 0, you add 6. Then from 0 to 8, you add 8. 8+6=14