Answer:
4050 gallons
Explanation:
In first half and hour both pumps are working property . There for it give, 45
gallons per minute . Half and hour is equal to 30 minutes.After one pump was broken only one pump is working 30 minutes .
For 1st 30 minutes ,( 2 pumps are working )
Gallons = 45 * 30 *2 = 2700 gallons
2nd 30 minutes ( 1 pump is working )
Gallons = 45*30*1 = 1350 gallons
Total gallons = 2700+1350
= 4050 gallons
Molly could increase her heart rate by turning around and jogging backwards, by jogging on her hands instead of her feet, or by continuing to jog normally but increasing the speed of the treadmill.
The amount of time saved on the 86.0 mile trip from Tulsa entrance to Oklahoma City is 0.42 hours
<h3>What is time?</h3>
Time is the measurement of a past, present, or future event. The S.I unit of time is seconds (s)
To get the time that was saved on the 8.6-mile trip, we use the formula below.
Formula:
- Ts = (d/v₁)-(d/v₂)................. Equation 1.
Where:
- Ts = Time saved on the trip
- d = distance covered during the trip
- v₁ = Initial legal speed limit
- v₂ = final/current legal speed limit.
From the question,
Given:
- d = 86.0 mile
- v₁ = 55.0 mi/h
- v₂ = 75.0 mi/h
Substitute these values into equation 1
- Ts = (86/55)-(86/75)
- Ts = 1.564-1.147
- Ts = 0.42 h.
Hence, The amount of time saved on the 86.0 mile trip from Tulsa entrance to Oklahoma City is 0.42 hours.
Learn more about time here: brainly.com/question/13893070
The correct answer is
<span>C. The current in the battery and in each resistor is the same.
In fact, when resistors are connected in series, the current flowing through them is the same in each resistor. This is also equal to the current flowing in the circuit, so it is the same as the current flowing through the battery.</span>
Answer:
Yes it is possible to increase the power with out changing the amount of work.
Explanation:
The power is defined by the amount of power divided by the time. This time is the one needed to do the work. We can understand this issue by analyzing an example with numeric values.
Work = 500 [J]
Time = 5 [s]
Power will be:
![Power=\frac{500}{5} \\Power=100 []watt]\\](https://tex.z-dn.net/?f=Power%3D%5Cfrac%7B500%7D%7B5%7D%20%5C%5CPower%3D100%20%5B%5Dwatt%5D%5C%5C)
Now if we change the time to 2 seconds:
![Power = 500 [J]/2[s]\\Power = 250 [watt]\\](https://tex.z-dn.net/?f=Power%20%3D%20500%20%5BJ%5D%2F2%5Bs%5D%5C%5CPower%20%3D%20250%20%5Bwatt%5D%5C%5C)
As we can see, the power was increased without the need to change the work.
