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kifflom [539]
3 years ago
8

if you use the compound pulley, you will need to pull twice the distance but with less force. the force you need is equal to one

half the weight of the box plus 25 N. what is the force needed?
Physics
1 answer:
algol133 years ago
6 0

Answer:

F= 25/2 = 12.5N

Explanation:

When you use a compound pulley the force required depends on the mechanical advantage of the compound pulley. This is known as rate of loss of distance or the ratio of the force to the load.

M.A = Effort distance /Load distance. OR M.A = Load/Effort

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What distance will be traveled if you are going 120km/hr for 30 min?
nikklg [1K]

Answer:

60 km

Explanation:

For an object (or a person, such as in this case) moving at constant speed, the speed is equal to the ratio between the distance travelled and the time taken:

v=\frac{d}{t}

where

v is the speed

d is the distance

t is the time taken

In this case, we have:

v = 120 km/h is the speed

t = 30 min = 0.5 h is the time taken

Therefore, we can rearrange the equation to find the total distance travelled:

d=vt=(120)(0.5)=60 km

3 0
3 years ago
What electric field strength would store 12.5 JJ of energy in every 6.00 mm3mm3 of space?
Tcecarenko [31]

To develop this problem we will apply the concepts related to the potential energy per unit volume for which we will obtain an energy density relationship that can be related to the electric field. From this formula it will be possible to find the electric field required in the problem. Our values are given as

The potential energy,  U = 13.0 J

The volume,  V = 6.00 mm^3 = 6.00*10^{-9}m^3

The potential energy per unit volume is defined as the energy density.

u = \frac{U}{V}

u= \frac{(13.0 J)}{(6.00*10^{-9} m^3)}

u= 2.167109 J/m^3

The energy density related with electric field is given by

u = \frac{1}{2} \epsilon_0 E^2

Here, the permitivity of the free space is

\epsilon_0 = 8.85*10^-{12} C^2/N \cdot m^2

Therefore, rerranging to find the electric field strength we have,

E = \sqrt{\frac{2u}{\epsilon_0}}

E = \sqrt{\frac{2(2.167109)}{8.85*10^{-12}}}

E = 2.211010 V/m

Therefore the electric field is 2.21V/m

8 0
3 years ago
If someone is driving 100 miles in 60 minutes then drives 150 miles in 100 minutes west, what is his acceleration rate.
Sliva [168]

Answer:

his acceleration rate is -0.00186 m/s²

Explanation:

Given;

initial position of the car, x₀ = 100 miles = 160, 900 m ( 1 mile = 1609 m)

time of motion, t₀ = 60 minutes = 60 mins x 60 s = 3,600 s

final position of the car, x₁ = 150 miles = 241,350 m

time of motion, t₁ = 100 minutes = 100 mins x 60 s = 6,000 s

The initial velocity is calculated as;

u = 160, 900 m / 3,600 s

u = 44.694 m/s

The final velocity is calculated as;

v = 241,350 m / 6,000 s

v = 40.225 m/s

The acceleration is calculated as;

a = \frac{\Delta V}{\Delta t} = \frac{v- u}{t_1 - t_ 0} = \frac{40.225  - 44.694}{6000-3600} = -0.00186 \ m/s^2\\\\

Therefore, his acceleration rate is -0.00186 m/s²

6 0
3 years ago
Match the following items.
Ray Of Light [21]

Answer:

Je ne Sachez que Qu’est-ce que le

8 0
2 years ago
When you look at yourself in the mirror, what is the approximate angle of incidence of the light rays?
Kitty [74]
46 degrees
I hope this helps :)
3 0
3 years ago
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