The 2nd has the most porosity
Infiltration
That's all I can answer for you. Hope it helps
Given Information:
Mass = m = 20000 kg
Height of ramp = h = 0.840 m
Length of ramp = L = 20 m
Required Information:
Uphill Force = F = ?
Answer:
F = 8232 N
Explanation:
The force can be found using the equation
F = mgsinθ
Where m is the mass of block, g is the acceleration due to gravity
Since the ramp can be modeled as an inclined plane so it can formed into a triangle, recall that in right angle triangle sinθ is equal to opposite over hypotenuse. The opposite is the height and hypotenuse is the ramp surface.
sinθ = h/L = 0.840/20 = 0.042
F = 20000*9.8*0.042
F = 8232 N
Therefore, an uphill force of 8232 N would be needed.
Answer:
a) Posición y velocidad después de los 6s
i) Posición = -26.58m
ii) velocidad = -33.86m/s
b) Tiempo para alcanzar la altura máxima
= 2.55s
c) Alcance horizontal
= 220.7m
Explanation:
a) Posición y velocidad después de los 6s
i) Posición
y = (usinθ)t – 1/2 gt²
u = 50m/s
θ = 30°
g = 9.81m/s²
t = 6s
y = (50 × sin 30)6 - 1/2 × 9.81 × 6²
y = 150 - 176.58
y = -26.58m
ii) velocidad
v = u sinθ–gt
u = 50m/s
θ = 30°
g = 9.81m/s²
t = 6s
v = 50 × sin 30 - 9.81 × 6
v = 25 - 58.86
v = -33.86m/s
b) Tiempo para alcanzar la altura máxima
usinθ /g
u = 50m/s
θ = 30°
g = 9.81m/s²
= 50 × sin 30/ 9.81
= 25/9.81
= 2.5484199796s
≈ 2.55s
c) Alcance horizontal
R = u²sin2θ/g
u = 50m/s
θ = 30°
g = 9.81m/s²
R = 50² ×( sin 2 ×30°) /9.81
R = 220.69964419m
≈ 220.7m
Answer:
11.85m
Explanation:
For the development of this problem we must resort to the concepts of the basic kinematic equations that define the distance of a body, such as speed for a certain time, that is,

From the information provided we say that the distance between the cretas is 0.6m,

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