Answer:
d = 0.076 mm
Explanation:
Given data
diffraction pattern d1 = 0.19 mm = 0.019 cm
separated s(1) = 1.8 cm
separated s(2) = 4.5 cm
to find out
d2 for an unknown
solution
we know here that spacing in between the diffraction fringe is always inversely proportional to diffraction grating so
we will apply here formula for unknown d that is
d1 (s1 / L) = d2 (s2 /L)
d2 = d1 × s(1) / s(2)
put here all thes evalue we get d2
d2 = d1 × s(1) / s(2)
d2 = 0.019 × 1.8 / 4.5
d2 = 0.0076 cm
d2 = 0.076 mm
Answer:
-2.79 m/s²
Explanation:
Given:
v₀ = 20 m/s
v = 11 m/s
Δx = 50 m
Find: a
v² = v₀² + 2aΔx
(11 m/s)² = (20 m/s)² + 2a (50 m)
a = -2.79 m/s²
Round as needed.
Force = (mass) x (acceleration) Newton's second law of motion.
Force = (2 kg) x (3 m/s²) = 6 newtons.
