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3 years ago

I need urgent help. which of these network has minimum data loss. a. LAN b. MAN c. WAN

Computers and Technology

1 answer:

Vinvika [58]3 years ago

6 0

Answer:

The correct option is;

a. LAN

Explanation:

The computer networks listed vary in their transmission medium from the wired transmission medium using the network cable for the Local Area Network (LAN) network, to the wireless transmission network used in the Wide Area Network (WAN), while the Wide Area Networks, (WAN) consists of several LAN networks connected to a larger network through telephone lines.

Of the three network types, the type that has the least amount of data loss is the LAN, due to its structure, being the smallest unit of wired network that can handle direct port to port data flow through physical network switches, which ensures sufficient bandwidth and lesser opportunity for congestion which results in packets of data losses.

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3 years ago

5)What are the differences in the function calls between the four member functions of the Shape class below?void Shape::member(S

Stells [14]

Answer:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

Explanation:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

The s1 and s2 objects are passed by value as there is no * or & sign with them. If any change is made to s1 or s2 object, there will not be any change to the original object.

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

The s1 and s2 objects are passed by pointer as there is a * sign and not & sign with them. If any change is made to s1 or s2 object, there will be a change to the original object.

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

The s1 and s2 objects are passed by reference as there is a & sign and not * sign with them. If any change is made to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

The s1 and s2 objects are passed by reference as there is a & sign and not * sign with them. The major change is the usage of const keyword here. Const keyword restricts us so we cannot make any change to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

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3 years ago

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Nesterboy [21]

Answer:

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Explanation:

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3 years ago

Write a program that accepts an integer value called multiplier as user input. Create an array of integers with ARRAY_SIZE eleme

Tasya [4]

Answer:

The program in C++ is as follows:

#include <iostream>

using namespace std;

void PrintForward(int myarray[], int size){

for(int i = 0; i<size;i++){ cout<<myarray[i]<<" "; }

}

void PrintBackward(int myarray[], int size){

for(int i = size-1; i>=0;i--){ cout<<myarray[i]<<" "; }

}

int main(){

const int ARRAY_SIZE = 12;

int multiplier;

cout<<"Multiplier: ";

cin>>multiplier;

int myarray [ARRAY_SIZE];

for(int i = 0; i<ARRAY_SIZE;i++){ myarray[i] = i * multiplier; }

PrintForward(myarray,ARRAY_SIZE);

PrintBackward(myarray,ARRAY_SIZE);

return 0;}

Explanation:

The PrintForward function begins here

void PrintForward(int myarray[], int size){

This iterates through the array in ascending order and print each array element

for(int i = 0; i<size;i++){ cout<<myarray[i]<<" "; }

}

The PrintBackward function begins here

void PrintBackward(int myarray[], int size){

This iterates through the array in descending order and print each array element

for(int i = size-1; i>=0;i--){ cout<<myarray[i]<<" "; }

}

The main begins here

int main(){

This declares and initializes the array size

const int ARRAY_SIZE = 12;

This declares the multiplier as an integer

int multiplier;

This gets input for the multiplier

cout<<"Multiplier: "; cin>>multiplier;

This declares the array

int myarray [ARRAY_SIZE];

This iterates through the array and populate the array by i * multiplier

for(int i = 0; i<ARRAY_SIZE;i++){ myarray[i] = i * multiplier; }

This calls the PrintForward method

PrintForward(myarray,ARRAY_SIZE);

This calls the PrintBackward method

PrintBackward(myarray,ARRAY_SIZE);

return 0;}

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3 years ago

X-1; while x ==1 disp(x) end, then the result a. infinity or b. (1)

Alex_Xolod [135]

Answer:

1 is the answer because ur trying to trick us

Explanation:

8 0

3 years ago

I need urgent help. which of these network has minimum data loss. a. LAN b. MAN c. WAN ​

I need urgent help. which of these network has minimum data loss. a. LAN b. MAN c. WAN