Answer:
Weight=686.7N, , S.G.=0.933, F=17.5N
Explanation:
So, the first value the problem is asking us for is the weight of methanol. (This is supposing there is a mass of methanol of 70kg inside the tank). We can find this by using the formula:
W=mg
so we can substitute the data the problem provided us with to get:
which yields:
W=686.7N
Next, we need to find the density of methanol, which can be found by using the following formula:
we know the volume of methanol is 75L, so we can convert that to like this:
so we can now use the density formula to find our the methanol's density, so we get:
Next, we can us these values to find the specific gravity of methanol by using the formula:
when substituting the known values we get:
so:
S.G.=0.933
We can now find the force it takes to accelerate this tank linearly at
F=ma
F=17.5N
Answer:
A wave of compression and rarefaction, by which sound is propagated in an elastic medium such as air.
Steel is more elastic than rubber<span> because </span>steel<span> comes back to its original shape faster </span>than rubber<span> when the deforming forces are removed, hope it helps :)</span>
Answer:
2.097×10^-5 N
Explanation:
Viscosity = mass/distance×time
time (t) = mass/viscosity×distance
Mass of steel part = 200 kg
Viscosity of oil = 0.065 N.s/m^2
Distance = 0.5 mm = 0.5/1000 = 5×10^-4 m
t = 200/0.065×5×10^-4 = 6.2×10^6 s
Force (F) = mass×velocity/time = 200×0.65/6.2×10^6 = 2.097×10^-5 N
Answer:
I think its chemical properties. forgive me if I'm wrong. Btw in in k12 too