The exact distance from the seismic station to the epicenter is 6000 km.
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Epicenter of earthquake</h3>
The earthquake's epicenter is the point above the fault location on the earth's surface.
Given that:
A p-wave arrives at 3:00:00 and the s-wave arrives at 3:07:20.
Difference in arrival time = 3:07:20 - 3:00:00 = 7 minutes 20 seconds
From the earthquake time travel graph, a time difference of 7 min 20 sec is at x = 6
The exact distance from the seismic station to the epicenter is 6000 km.
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Answer:
6km
Explanation:
3hours X 2km = 6 kilometres
Answer:
The lowest possible frequency of sound for which this is possible is 1307.69 Hz
Explanation:
From the question, Abby is standing 5.00m in front of one of the speakers, perpendicular to the line joining the speakers.
First, we will determine his distance from the second speaker using the Pythagorean theorem
l₂ = √(2.00²+5.00²)
l₂ = √4+25
l₂ = √29
l₂ = 5.39 m
Hence, the path difference is
ΔL = l₂ - l₁
ΔL = 5.39 m - 5.00 m
ΔL = 0.39 m
From the formula for destructive interference
ΔL = (n+1/2)λ
where n is any integer and λ is the wavelength
n = 1 in this case, the lowest possible frequency corresponds to the largest wavelength, which corresponds to the smallest value of n.
Then,
0.39 = (1+ 1/2)λ
0.39 = (3/2)λ
0.39 = 1.5λ
∴ λ = 0.39/1.5
λ = 0.26 m
From
v = fλ
f = v/λ
f = 340 / 0.26
f = 1307.69 Hz
Hence, the lowest possible frequency of sound for which this is possible is 1307.69 Hz.
Answer: the work will also increase by double
Explanation:
This is because they are directly proportional in the formula w=f x d
Answer:b
Explanation:
Given
Woman earn 50% more than her husband
Total sum of their money is
Suppose man earns
so women earns
Sum of their money is
Women earns