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Dmitrij [34]
3 years ago
13

In doing a load of clothes, a clothes drier uses 18 A of current at 240 V for 41 min. A personal computer, in contrast, uses 2.2

A of current at 120 V. With the energy used by the clothes drier, how long (in hours) could you use this computer to "surf" the Internet
Physics
1 answer:
Tpy6a [65]3 years ago
4 0

Answer:

The time taken by the personal computer to 'surf' the internet is 11.13 h.

Explanation:

The expression for the energy in terms of current and time is as follows;

E= Vit

Here, V is the potential, i is the current and t is the time.

According to question, in doing a load of clothes, a clothes drier uses 18 A of current at 240 V for 41 min.

Convert time from minute to second.

t=\frac{41}{60}s

Calculate the energy used by the clothes drier.

Put V= 240 V, t=\frac{41}{60}s and i=18 A in the expression for the energy.

E= (240)(18)\frac{41}{60}

E'= 2937.6 W

Therefore, the energy of a clothes drier is E'= 2937.6 W.

It is given in the problem that a personal computer, in contrast, uses 2.2 A of current at 120 V. With the energy used by the clothes drier, this computer is used to surf the internet.

Calculate the time taken by the computer to 'surf' the internet.

E'=V'i't'

Here, V' is the voltage used by the a personal computer, i' is the current and t' is the time taken by the personal computer.

Put E'= 2937.6 W, V= 120 V and i'= 2.2 A.

2937.6 = (120)(2.2)t'

t'=\frac{2937.6}{264}

t'= 11.13 h

Therefore, the time taken by the personal computer to 'surf' the internet is 11.13 h.

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When light generated by a lamp in a light microscope passes into a lens, the speed of the light _______ because the glass lens h
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3 years ago
How long does it take for a 3.5 kW electric water heater to heat 40 kg of water? from 20 ° C to 75 ° C? The specific heat capaci
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Answer:

2633.7 s

Explanation:

From the question,

Heat lost by the water heater = Heat gained by the water

Applying,

P = cm(t₂-t₁)/t.................. Equation 1

Where P = power of the heat, c = specific heat capacity of water, m = mass of water, t₁ = initial temperature, t₂ = final temperature, t = time

make t the subject of the equation

t = cm(t₂-t₁)/P.............. Equation 2

From the question,

Given: c = 4190 J/kgK, P = 3.5 kW = 3500 W, m = 40 kg, t₁ = 20°C, t₂ = 75°C

Substitute these values into equation 2

t = 4190×40(75-20)/3500

t = 9218000/3500

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4 0
2 years ago
QiC S A particle of mass m moves along a straight line with constant velocity v→ in the x direction, a distance b from the x axi
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The angular momentum is m v b where b is known as the impact parameter.

<h3>What is mass?</h3>
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  • The kilogram is the SI unit of mass (kg). In science and technology, a body's weight in a given reference frame is the force that causes it to accelerate at a rate equal to the local acceleration of free fall in that frame.
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Does the particle possess any angular momentum about the origin?

The angular momentum is m v b, where b is known as the impact parameter.

To learn more about mass, refer to:

brainly.com/question/3187640

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7 0
1 year ago
A 4.00 kg ball is swung in a circle on the edge of a 1.50 m rope. The time it takes for the ball to complete one rotation is 3.4
lorasvet [3.4K]

Answer:

The answer is below

Explanation:

The length of the rope is equal to the radius of the circle formed by the complete rotation of the rope. Therefore the radius = 1.50 m.

a) The distance covered by the rope when completing one rotation is the same as the perimeter of the circle. Hence:

Distance covered in one rotation = 2π * radius = 2π * 1.5 = 3π meters

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b) The initial velocity (u) is 0 m/s, the final velocity is 2.77 m/s during time (t) = 3.4 s. Hence acceleration (a):

v = u + at

2.77 = 3.4a

a = 0.82 m/s²

c) Force on ball = mass * acceleration = 4 * 0.82 = 3.28 N

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