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harkovskaia [24]

3 years ago

10

Farah saved $15 everyday while shirley saved $10 everyday. Shirley started saving money 5 days earlier than Farah. How many days

will it take Farah to have the same amount of savings as Shirley?

1 answer:

vitfil [10]3 years ago

3 0

Answer:

6 days

Step-by-step explanation:

shirley earned 50 dollars before farah started saving

50-15

60-30

70-45

80-60

90-85

100-100

6 days

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Which of the following expressions are equivalent? Justify your reasoning.

Fynjy0 [20]

A. $4\sqrt{x^{3}$
    $4\sqrt{x^{2} * x}$
    $4\sqrt{x^{2}}\sqrt{x}$
    $4x\sqrt{x}$

b. $\frac{1}{x^{-1}} =x$

c. $10\sqrt{x^{5} * x^{4} * x^{2}}$
    $10\sqrt{x^{11}$
    $10\sqrt{x^{10}* x}$
    $10\sqrt{x^{10}}\sqrt{x}$
    $10x^{5}\sqrt{x}$

d. $x^{\frac{1}{3}} * x^{\frac{1}{3}} * x^{\frac{1}{3}}$
    $x$

The expressions that are equivalent are B and D.

3 0

3 years ago

Can someone please explain how to do this?

vovikov84 [41]

Answer:

14)

tan θ = BC/AC = 9/13
θ = arctan (9/13)
θ = 34.7°

15)

cos 45° = 14/x
x = 14 / cos 45°
x = 19.8

6 0

3 years ago

Write an equation of a line that has a slope of 5 and goes through the point (-8, 35)?

MrRa [10]

Y = 5x + b
Plug in the point
35 = 5(-8) + b
35 = -40 + b, b = 75
Solution: y = 5x + 75

7 0

3 years ago

One of the largest pumpkins ever grown weighed about 3 over 4 ton. How many pounds did the pumpkin weigh???

Naily [24]

Since a ton is 2000 pounds, 2000/4=500. 500*3=1500 The pumpkin weighs 1,500 pounds.

You can also just do 2000*3/4=6000/4=1,500

6 0

4 years ago

Read 2 more answers

How to find the perimeter of the triangle

Sliva [168]

Answer:

A. 26.2

Step-by-step explanation:

To find the perimeter of the triangle, you have to find the distances of all three lines and add them up.

<u>Line AB</u>

Let's start off by finding the distance of line AB.

We will use the formula, $d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ .

Point A is (-2,5) and Point B is (4,-3).

To substitute the values, it will get to $d = \sqrt{(4--2)^{2}+(-3-5)^{2}}$ which in other words is $d = \sqrt{(4+2)^{2}+(-3-5)^{2}}$ .

Now we have to solve the parenthesis to get $d = \sqrt{(6)^{2}+(-8)^{2}}$ .

Now we have to solve the exponents which would get to $d = \sqrt{36+64}$ .

Now we have to simplify the square root to $d = \sqrt{100}$ . In other words, that is $d = 10$ .

Line AB = 10

<u>Line BC</u>

Now let's find the distance of line BC.

We will use the same formula, $d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ .

Point B is (4,-3) and Point C is (0,-6).

To substitute the values, it will get to $d = \sqrt{(0-4)^{2}+(-6--3)^{2}}$ which in other words is $d = \sqrt{(0-4)^{2}+(-6+3)^{2}}$ .

Now we have to solve the parentheses to get $d = \sqrt{(-4)^{2}+(-3)^{2}}$ .

Now we have to solve the exponents which would get to $d = \sqrt{16+9}$ .

Now we have to simplify the square root to $d = \sqrt{25}$ . In other words, that is $d = 5$ .

Line BC = 5.

<u>Line AC</u>

Now let's fine the distance of line AC.

We will use the same formula, $d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ .

Point A is (-2,5) and Point C is (0,-6).

To substitute the values, it will get to $d = \sqrt{(0--2)^{2}+(-6-5)^{2}}$ which in other words is $d = \sqrt{(0+2)^{2}+(-6-5)^{2}}$ .

Now we have to solve the parentheses to get $d = \sqrt{(2)^{2}+(-11)^{2}}$ .

Now we have to solve the exponents which would get to $d = \sqrt{4+121}$ .

Now we have to simplify the square root to $d = \sqrt{125}$ . In other words, that is $d = 5\sqrt{5}$ . To round that, $d = 11.2$ .

Line AC = 11.2.

<u>Perimeter of Triangle ABC</u>

Perimeter of Triangle ABC = Line AB + Line BC + Line AC.

Perimeter of Triangle ABC = 10 + 5 + 11.2

Perimeter of Triangle ABC = 26.2

Hope this helped! If not, please let me know <3

3 0

3 years ago