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a_sh-v [17]
3 years ago
13

What is the equation of this function after it is reflected over the x-axis?

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
5 0

Answer: F(x)=-(x+4)^3

That's it

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The function r(x) = x^2 + 6x + 9. What is the vertex of g(x) = r(x) - 2?
sladkih [1.3K]

Answer:

The vertex of g(x) is (-3, -2).

Step-by-step explanation:

To find what g(x) truly represents, we must substitute r(x) with the function itself to get the derived function g(x).

g(x) = r(x) - 2

g(x) = x² + 6x + 9 - 2    (Simplify)

g(x) = x² + 6x + 7    (Now, we can start to find the vertex of this quadratic function)

The vertex can be found, when the function is in standard form (AX² + BX + C), by this defined ordered pair: (\frac{-b}{2a}, y)

Notice that we already know what A, B, and C are, so we don't need to worry about them, but we don't have the y value. This can be calculated by plugging in the x value for the axis of symmetry which is (-b) / (2a). The vertex is always at the axis of symmetry and so, by plugging in the x value for the axis of symmetry, we can find the exact y value for the location of the vertex on the cartesian plane.

A = 1, B = 6, C = 7 in the quadratic function g(x).

The x value for the vertex can be found by:

x = (-6) / 2(1)    (Simplify)

x = -3

Now that we have x, we can find y by substituting this into g(x):

g(x) = (-3)² + 6(-3) + 7    (Simplify)

g(x) = 9 - 18 + 7    (Simplify)

g(x) = -2

The y value for our vertex is -2.

The vertex of g(x) is (-3, -2).

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Step-by-step explanation:

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2/4 = 1

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