1. The bird has to adjust where it doves in for the fish because the light is refracted by the water, making it look like the fish is in a different position than it is.
2. The clock is reflected in the mirror, which sends each part of the image straight back.
4. Your first part is correct. The second part: The plant would look dark brown or black and red light. Red light has no green wavelengths to reflect, and the red light would be absorbed by the leaf, making it appear almost black.
LMK if you have questions.
Answer:
If this trend continues, the following week will be cooler, and a large amount of rain will fall.
Explanation:
Patterns and trends can often be found in data sets. During the week that Cho recorded the weather, the temperatures consistently dropped by one to four degrees each day. At the end of the week, the amount of precipitation increased daily.
It will be extracted only 1/3 of NaCl less in 10 mL of water than in 30 mL of water.
If it is known that solubility of NaCl is 360 g/L, let's find out how many NaCl is in 30 mL of water:
360 g : 1 L = x g : 30 mL
Since 1 L = 1,000 mL, then:
360 g : 1,000 mL = <span>x g : 30 mL
Now, crossing the products:
x </span>· 1,000 mL = 360 g · 30 mL
x · 1,000 mL = 10,800 g mL
x = 10,800 g ÷ 1,000
x = 10.8 g
So, from 30 mL mixture, 10.8 g of NaCl could be extracted.
Let's calculate the same for 10 mL water instead of 30 mL.
360 g : 1 L = x g : 10 mL
Since 1 L = 1,000 mL, then:
360 g : 1,000 mL = <span>x g : 10 mL
Now, crossing the products:
x </span>· 1,000 mL = 360 g · 10 mL
x · 1,000 mL = 3,600 g mL
x = 3,600 g ÷ 1,000
<span>x = 3.6 g
</span>
<span>So, from 10 mL mixture, 3.6 g of NaCl could be extracted.
</span>
Now, let's compare:
If from 30 mL mixture, 10.8 g of NaCl could be extracted and <span>from 10 mL mixture, 3.6 g of NaCl could be extracted, the ratio is:
</span>3.6/10.8 = 1/3
Therefore, i<span>t will be extracted only 1/3 of NaCl less in 10 mL of water than in 30 mL of water. </span>
Answer: Option (a) is the correct answer.
Explanation:
Non-metals are the species which in order to complete their octet readily gain an electron.
For example, fluorine is a non-metal with atomic number 9 and its electronic distribution is 2, 7.
Hence, to attain stability it readily accepts an electron from a donor atom.
Some characteristics of non-metals are as follows.
Non-metals do not conduct electricity.
Non-metals are brittle in nature and they have a rough surface.
Non-metals are not malleable or ductile.
Thus, we can conclude that non-metals do not conduct electricity is a characteristic of non-metals.
