An endothermic process is a process that needs energy in order to proceed. This is the opposite of exothermic which is a process of releasing energy. During an endothermic process, the temperature of the system is increased thus exciting the molecules and allowing them to move faster. This will cause liquid to vaporize.
Question:
how many significant figures are in the measurement 0.0056 ke?
a. four
b. two
c. five
d. three
answer:
b. two
Answer:
EXPERIMENT: THE CABBAGE INDICATOR
Here are your goals for this lesson:
Use indicator for each substance to determine if substance is an acid or a base
Summarize results and the experimental method
You can use the natural indicator in red cabbage juice to determine which household liquids are acids or bases. If no change in the color of the cabbage juice takes place, the liquid is neither an acid nor base; it is neutral.
Acids and bases are opposites. When an acids and base are mixed, they neutralize each other. You can use an indicator to see the neutralized reaction. The cabbage juice will change color when the liquids are neutralized.
Online Lab
This video will demonstrate how an indicator, in this case, cabbage indicator, can be used to determine whether a solution is acidic or basic. As you watch the video, remember to record your data and observations to use to present your findings.
Compile a summary of your findings from this experiment. Include your hypothesis, observations, data, and conclusions. Be sure to answer the questions below as well as explaining the method and results.
r.
Explanation:
2Pb(NO₃)₂ = 2PbO + 4NO₂ + O₂
m{Pb(NO₃)₂}=9.9 g
m'{PbO}=5.5 g
M{Pb(NO₃)₂}=331.2 g/mol
M{PbO}=223.2 g/mol
w-?
w=m'{PbO}/m{PbO}
m{PbO}=M{PbO}m{Pb(NO₃)₂}/M{Pb(NO₃)₂}
w=m'{PbO}M{Pb(NO₃)₂}/[M{PbO}m{Pb(NO₃)₂}]
w=5.5*331.2/[223.2*9.9]=0.8244 (82.44%)
C = covalent
I = Ionic
(I'm lazy to an extent)
An ionic bond is between a metal and a nonmetal, and a covalent bond is between 2 nonmetals.
H2 = C
Cl2 = C
O2 = C
HCl = C
LiF = I
NaCl = I
NaF = I
MgF = I
NH3 = C
CH4 = C
CO2 = C
NaP = I
N2 = C
NF3 = C
