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Alex Ar [27]
3 years ago
11

Carbon dioxide and ____ are outputs of cellular respiration

Chemistry
1 answer:
vova2212 [387]3 years ago
5 0

Answer:

oxygen

Explanation:

plants use oxygen

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A sample of aluminum absorbs 9.86 J of heat, upon which the temperature increases from 23.2°C to 30.5°C. Since the specific heat
True [87]

Answer:

1.50 g

Explanation:

The heat absorbed by the aluminum in this case is:

q = m x C x ΔT     m= q/ (C x ΔT)

q= 9.86 J

C = 0.90 J/g-K

ΔT = ( 30.5 ºC - 23.2 ºC ) = 7.3 ºC = 7.3 K (this is a range of temperature)

m = 9.86 J / ( 0.90 J/g-K ) x 7.3 K ) = 1.50 g

8 0
3 years ago
Which type of fuel can only be used in certain geographic area? A. natural gas B. nuclear C. solar D. Biomass
poizon [28]

Answer:

A

Explanation:

6 0
3 years ago
What is the mass of CO2 lost at 20 min from the limestone sample?
harkovskaia [24]

Answer:

The mass, CO2 and CO3 from the limestone sample is discussed below in details.

Explanation:

(A) mass loss of sample of limestone after 20 min

= 0.8437g-0.5979g = 0.2458 g

From the given reaction of limestone, 2 mol of the sample gives 2 moles of CO 2.

Therefore  

184.4 g ( molar mass of limestone) gives2× 44 g of carbon dioxide.

1 g of sample gives 88/184.4 g of carbon dioxide

Hence 0.2458 g sample gives

= 88/184.4 × 0.2458 g = 0.117 g carbon dioxide

(B) mole of CO 2 lost = weight/ molar mass

= 0.117 g / 44 g/mol =0.0027 mole

(C). 1 mol of limestone contain 2 mol of carbonate ion

From the reaction we know that carbonate ion of limestone is converted into carbondioxide

Hence lost carbonate ion = 0.2458 g

(D) we know that

1 mol limestone contain 1mol CaCO​​​ 3

Hence in sample present CaCO​​​ 3

= 1mole / 184.4 g × 0.8437 g= 0.00458 mol CaCO​​​3

8 0
3 years ago
Sulfur trioxide, so3, is made industrially in enormous quantities by combining oxygen and sulfur dioxide, so2. what amount (mole
DedPeter [7]

The answer is 37.5 moles

The explanation:

1- when we have the mass of SO3 in Kg so, first we have to convert it to grams:

mass = 3 * 1000 = 3000 g

2- we need to get the molar mass of SO3 :

molar mass of SO3 = 32 + (16*3)

= 80 g/mol

3- then we can use this formula to get number of moles:

moles = mass / molar mass

= 3000 g / 80 g/mol

= 37.5 moles

6 0
3 years ago
The ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. in t
Debora [2.8K]

The complete balanced chemical equation is: 
4 NH3 (g) + 5 O2 (g) → 4 NO (g) + 6 H2O (g) 

In statement form: 4mol NH3 reacts with 5 mol O2 to produce 6 mol H2O 

First let us find for the limiting reactant: 
>molar mass NH3 = 17 g/mol 
moles NH3 = 54/17 = 3.18 mol NH3 
This will react with 3.18*5/4 = 3.97 mol O2 

>molar mass O2 = 32g/mol 
moles O2 = 54/32 = 1.69 mol O2 
We have insufficient O2 therefore this is the limiting reactant 

From the balanced equation: 
For every 5.0 mol O2, we get 6.0 mol H2O, therefore

moles H2O formed =  1.69 mol O2  * 6/5 = 2.025 mol
Molar mass H2O = 18g/mol 
<span>mass H2O formed = 2.025*18 = 36.45 grams H2O produced</span>

8 0
3 years ago
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