The cloud that produces rain is the cumulonimbus cloud.
Answer:
11.9 g of nitrogen monoxide
Explanation:
We'll begin by calculating the number of mole in 6.75 g of NH₃. This can be obtained as follow:
Mass of NH₃ = 6.75 g
Molar mass of NH₃ = 14 + (3×1)
= 14 + 3
= 17 g/mol
Mole of NH₃ =?
Mole = mass /molar mass
Mole of NH₃ = 6.75 / 17
Mole of NH₃ = 0.397 mole
Next, we shall determine the number of mole of NO produced by the reaction of 0.397 mole of NH₃. This can be obtained as follow:
4NH₃ + 5O₂ —> 4NO + 6H₂O
From the balanced equation above,
4 moles of NH₃ reacted to produce 4 moles of NO.
Therefore, 0.397 mole of NH₃ will also react to produce 0.397 mole of NO.
Finally, we shall determine the mass of 0.397 mole of NO. This can be obtained as follow:
Mole of NO = 0.397 mole
Molar mass of NO = 14 + 16 = 30 g/mol
Mass of NO =?
Mass = mole × molar mass
Mass of NO = 0.397 × 30
Mass of NO = 11.9 g
Thus, the mass of NO produced is 11.9 g
Answer: 
Explanation:
Given : Sample size : n= 30 , it means it is a large sample (n≥ 30), so we use z-test .
Significance level : 
Critical value: 
Sample mean : 
Standard deviation : 
The formula to find the confidence interval is given by :-

i.e. 
i.e. 

Hence, the 95% confidence interval for the mean mpg in the entire population of that car model = 
<span>The water molecules that are evaporationg absorb heat energy from the surrounding environment, which causes the evaporation. If 5 grams of water evaporate, then there will be 5 grams of water vapor in the air.
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Answer:
Argon {Ar}
Explanation:
The noble gas used for a condensed electron configuration is the one before the element which you are configuring.
In this case, the element (Mn) is manganese
The noble gas that is before this element is Argon which is the row above it
so your configuration would be {Ar} 3d^5 4s^2