FACTOR ALL OF THE EQUATIONS INTO "y = (x-h)^2 + k," AND THE EQUATION'S VERTEX IS (h,k)
10. y = (x+2)^2 - 11 --> (-2, -11)
11. y = -(x-4)^2 + 32 --> (4, 32)
12. y = 3(x-1)^2 - 5 --> (1, -5)
13. y = -2(x+2)^2 + 5 --> (-2, 5)
14. y = 2(x+1)^2 - 1 --> (-1, -1)
15. y = -5(x-1)^2 + 8 --> (1, 8)
16. y = 3(x-3)^2 - 26 --> (3, -26)
17. y = (x+5)^2 - 32 --> (-5, -32)
18. y = -(x-3)^2 + 10 --> (3, -10)
Answer:
1079
Step-by-step explanation:
Hello,
18-5 = 13
31-18=13
44-31=13
161=5+13*12
So we need to compute

Thanks
difference of squares means that both the terms are square terms. (also there must be a - symbol)
for example
y^2 - 4
square root of y^2 is y
square root of 4 is +2 as well as -2
so you would factorise it like this:
(y+2)(y-2)
1. y^4 has a square root of y^2 as y^2 × y^2 is y^4.
<em>h</em><em>o</em><em>w</em><em>e</em><em>v</em><em>e</em><em>r</em><em>,</em><em> </em>-2 doesnt have a whole number square root so it is not a difference of squares.
2. 25 has a square root of 5. m^2 has a square root of m. n^4 has a square root of n^2. so this 25m^2n^4 is a square term.
1 has a square root of +1 and -1.
therefore, this one is a difference of squares. <u>(</u><u>5</u><u>m</u><u>n</u><u>^</u><u>2</u><u> </u><u>+</u><u>1</u><u>)</u><u> </u><u>(</u><u>5</u><u>mn^2</u><u> </u><u>-</u><u>1</u><u>)</u>
3. p^8 has a square root of p^4. q^4 has a square root of +q^2 and -q^2)
so it is a difference of squares. <u>(</u><u>p</u><u>^</u><u>4</u><u>+</u><u>q</u><u>^</u><u>2</u><u>)</u><u>(</u><u>p</u><u>^</u><u>4</u><u> </u><u>-</u><u>q</u><u>^</u><u>2</u><u>)</u>
4. 16x^2 is a square term as irs square root is 4x.
<em>h</em><em>o</em><em>w</em><em>e</em><em>v</em><em>e</em><em>r</em><em>,</em><em> </em>24 is not a square term.
therefore, it is not a difference of squares.
P(G) is 26/52
P(H) is 8/52
See the rest in the photo
Answer:
there is a feature on this app where u can take a picture and it will give u the answer. i would suggest trying that because it is quite useful