Taken time is from 11.00 am to 2.30 pm (14.30) = 14.30 - 11 = 3.30 hours
We know that D = S* T (D - distance, S - speed , T- time)
So,
X=3
x is the width of the sidewalk
The outside dimensions of the walkway are 12 + 2x by 8 + 2x
The total area is (12 + 2x)(8 + 2x)
The total area minus the area of the pool should be equal to the area of the pool
Hoped this helped!
Q.q i dunno , seems like he doesnt have enough money with the 6 deposites of 35.5 = 213 if you add the deposists to 420+213=633 , and he needs 4 checks of 310 eaach , he could only write 2 checks , so i suppose theirs not enough information to accumulate a answer
u - v = <5, 2> - <2, - 3> = <5 - 2, 2 + 3> = <3, 5>
given a vector <u, v> then the magnitude is √ (u² + v² ) and it's angle of direction is
θ = 
(
)
thus the magnitude of <3, 5> = √(3² + 5²) = √34 ≈ 5.83 ( to 2 dec. places )
Θ = (
) = 59.04° ( to 2 dec. places )
To find the intersection points, you take x^2 - 4x + 9 = -2x + 17
This gives x^2 - 2x - 8 = 0,
which factorises to (x - 4)(x + 2) = 0, giving the solutions x = 4 or x = -2
From the graph, we can see that x is positive, meaning x = 4, so a = 4.
Substituting x = 4 into y = -2x + 17, we get y = -2(4) + 17 = 9, so b = 9.
a + b = 4 + 9 = 13. The answer is B.
