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MariettaO [177]
3 years ago
9

Please help me I will give you extra points and the brain thing. (image below) 3/5

Mathematics
1 answer:
JulsSmile [24]3 years ago
4 0
I think the answer is A
You might be interested in
What is the HCF of 7 and 13​
gladu [14]
Answer:

The HCF of 7 and 13 is 1

Step-by-step explanation:

Prime numbers only have one factor which is 1 and itself
•••••••••••••••••••••••••••••••
doomdabomb: All brainliest
and thanks are appreciated
and would mean a lot to me,
thanks!
3 0
3 years ago
What is the volume of a sphere with a radius of 3 inches?
Vilka [71]

Answer:

36π cubic inches

Step-by-step explanation:

V = 4/3 πr³

radius (r): 3

= 4/3π(3)³

= 4/3π (27)

= 36π

3 0
3 years ago
I’m having trouble with this problem. Please help
iVinArrow [24]

The software rendering this question really butchered it... I think it's saying the displacement vector for the particle is

\vec r(t) = \sin(t) \, \vec\imath + 4t^3 \, \vec\jmath + 5t \, \vec k

Differentiate twice with respect to time t to get the velocity and acceleration vectors, respectively:

\dfrac{d\vec r}{dt} = \vec v(t) = \cos(t) \,\vec\imath + 12t^2 \,\vec\jmath + 5 \,\vec k

\dfrac{d^2\vec r}{dt^2} = \dfrac{d\vec v}{dt} = \vec a(t) = -\sin(t) \,\vec\imath + 24t \,\vec\jmath

Then at t=3, the acceleration of the particle is

\vec a(3) = -\sin(3)\,\vec\imath + 72\,\vec\jmath

which most closely resembles the first choice.

4 0
2 years ago
If the asymptotes of a hyperbola are the x- and y-axes, it is known as a rectangular hyperbola?
aleksandr82 [10.1K]
Yes, This is true. If the asymptotes of a hyperbola are the x- and y- axes, it IS known as a rectangular hyperbola.
3 0
3 years ago
A volleyball has a surface area of 1 465cm^2 Calculate the volume of five volleyballs. Round your answer to the nearest THOUSAND
Dmitriy789 [7]

The volume of five volleyballs is 26310.15 cubic cm if the volleyball has a surface area of 1465 square cm.

<h3>What is a sphere?</h3>

It is defined as three-dimensional geometry when half-circle two-dimensional geometry is revolved around the diameter of the sphere that will form.

We know the surface area of the sphere is given by:

SA = 4πr²

1465 = 4πr²

r = 10.79 cm

Volume of the sphere = 4πr³/3

V = 4π(10.79)³/3

V = 5262.03 cubic cm

Volume of five volleyballs = 5×5262.03 = 26310.15 cubic cm

Thus, the volume of five volleyballs is 26310.15 cubic cm if the volleyball has a surface area of 1465 square cm.

Learn more about the sphere here:

brainly.com/question/11374994

#SPJ1

8 0
2 years ago
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