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Kruka [31]
3 years ago
14

1. Investigate if there is an association between survival past 500 days and treatment group.(a) Create a variable that indicate

s whether each observation survived >= 500 days.(b)What are the two tests that could be used to answer this question? What are the null andalternative hypotheses for each test? When is each test appropriate?(c)Perform the chi-squared test to investigate if there is an association between survival past 500 daysand treatment group. Does one treatment group have a better outcome than the other? Write abrief paragraph to summarize your results. Your summary does not need to include a confidenceinterval, but it should include basic descriptive statistics.(d)Explain why the analysis performed is not sufficient to make definitive conclusions regarding theefficacy of the two treatment groups.
Mathematics
1 answer:
vekshin13 years ago
3 0

Answer:

There is association between survival and treatment H1: there is no association between survival and treatment.

Step-by-step explanation:

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Answer:

H_0:\mu  = 45 and H_a:\mu  < 45

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Step-by-step explanation:

Given

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From the question, a previous census shows that:

\mu =45 and \sigma= 9.1

This is the null hypothesis i.e.

H_0:\mu  = 45

Reading further, a new test was to show whether the average has decreased.

This is the alternate hypothesis, and it is represented as:

H_a:\mu  < 45

Solving (b) and (c): The test statistic (T).

This is calculated using:

T = \frac{\mu}{\sigma/\sqrt n}

In this case:

n = 50   \mu =45 and \sigma= 9.1

So:

T = \frac{45}{9.1/\sqrt{50}}

T = \frac{45}{9.1/7.07}

T = \frac{45}{1.29}

T = 34.88

Solving (c): Accept or reject null hypothesis

\alpha = 0.05

First calculate the degrees of freedom (df)

df = n - 1 = 50 - 1

d f = 49

From the t distribution table,

At: d f = 49,  \alpha = 0.05 and T = 34.88

the t score is:

p = 1.676

p > 0.05

<em>So, the null hypothesis is not rejected</em>

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Answer:

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3 years ago
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kupik [55]

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This means that, whenever the black graph associates

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So, the equation for the red graph is

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Step-by-step explanation:

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