Given the answers of 100 students surveyed, you have to find the following probability:
<em>P(taken a public speaking class | majoring in business administration)</em>
This is the probability that the student has taken a public speaking class, given that he is majoring in business administration, which is a conditional probability.
We already know that the student is majoring in business administration, so instead of working with the information about the 100 students, you can directly work with the group os students that are doing that major:
You can determine this probability as the quotient between the students that took a public speaking class and are majoring in business and the total number of students that are majoring in business:
![P(public.class|bu\sin ess.major)=\frac{10}{55}](https://tex.z-dn.net/?f=P%28public.class%7Cbu%5Csin%20ess.major%29%3D%5Cfrac%7B10%7D%7B55%7D)
So, the probability is 10/55
Answer:
c
Step-by-step explanation:
I believe the answer is C because you need to find a number that is multiplied by the exponent 3 to equal 1433 in, by which you have to find the cubed root of 1433.
First let's start with the relationship between grams and centigrams and grams and milligrams.
1 gram = 100 centigrams
1 gram = 1000 milligrams
Because these two equations are equal, we can rewrite our equation as 100 centigrams = 1000 milligrams.
Now we divide by 100 to simplify our equation to 1 centigram = 10 milligrams.
With this simplified equation we see that we multiply the number of centigrams by 10 to find the equal number of milligrams.
95% of 57 is 54.15 and 33% of 44 is 14.52