Answer:
<em>{9,19,39,79}</em>
Step-by-step explanation:
<u>Recursive Sequences</u>
The recursive sequence can be identified because each term is given as a function of one or more of the previous terms. Being n an integer greater than 1, then:
f(n) = 2f(n-1)+1
f(1) = 4
To find the first four terms of the sequence, we set n to the values {2,3,4,5}
f(2) = 2f(1)+1
Since f(1)=4:
f(2) = 2*4+1
f(2) = 9
f(3) = 2f(2)+1
Since f(2)=9:
f(3) = 2*9+1
f(3) = 19
f(4) = 2f(3)+1
Since f(3)=19:
f(4) = 2*19+1
f(4) = 39
f(5) = 2f(4)+1
Since f(4)=39:
f(5) = 2*39+1
f(5) = 79
Answer:
These are the answers...
Step-by-step explanation:
6 is a solution.
10 is not a solution.
-5 is a solution.
9 is a solution.
12.5 is not a solution.
0 is a solution.
<span>This question, in my opinion, is not well stated. If f(x) = √x, as the question statement seems to say, then the domain is not x<7. Rather, the domain is x≥0.
If f(x) is not the square root function, but say f(x) = √(7-x) then the domain is x≤7, and for this function then the appropriate answer is d), since the x-term inside the radical has a negative coefficient.</span>
<span>The answer: b. translated according to the rule (x, y) → (x + 8, y + 2) and reflected across the x-axis
If you make the drawing of the situation you realize the you need a reflection through the x-axis, but first you need to translate the polygon several units to the left and upward.
You can see that all the x-coordinates have increased 8 units, so the solution has to include x + 8.
Also, you see that you have to move the polygon 2 units upward before doing the reflection so the solution has to include y + 2.
So, the answer is (x,y) ---> (x + 8, y + 2) and then reflection across the x-axis.
</span>
1) V.A, J.L, C.T, R.R, T.Mc
2) J.L, R.R, C.T, V.A, T.Mc
3) C.T, J.L, R.R, V.A, T.Mc
4) C.T, V.A, T.Mc, J.L, R.R
5) C.T, V.A, J.L, T.Mc, R.R
