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Ghella [55]
3 years ago
7

Can someone PLEASEEEEEEE tell me 5 ways to solve -2x<10 ?

Mathematics
1 answer:
bezimeni [28]3 years ago
6 0

Answer:

Divide each term by −2 and simplify.

Inequality Form:

x>−5

Interval Notation:

(−5,∞)

Isolate the variable by dividing each side by factors that don't contain the variable.

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Which of the following verifies that AABC is similar to A DEF?
emmainna [20.7K]

Answer:

D

Step-by-step explanation:

According to the SAS theorem, if the 2 sides of the 2 triangles are multiples of each other by the same scale factor, with the angle in between them being the same for each triangle. The triangles are similar.

The SSS theorem is not appropriate here because we do not know the side lengths of AB or DE in the diagram. For SSS theorem we need to know all of the side lengths.

A is incorrect because the similarity can be determined.

6 0
4 years ago
Read 2 more answers
Which expressions show the expanded form for 907.03? my choices are; (
PtichkaEL [24]
The answer is b hope this helps
4 0
3 years ago
Please help!! The answers with red arrows are wrong!
Anika [276]
The correct answer is the second one I think
g + 5 > 12; g > 7
5 0
3 years ago
Some help me please :( I really need help with this
katrin2010 [14]
First part, in quadrilateral WXYZ, WX is parallel to ZY because both sides are equal while the other parallel segments WZ and XY are equal but different side lengths.

The measure of angle Z is 78 because both of the pictures are the same, only rotated. and angle S and Z are acute.
7 0
3 years ago
Find Exact Answers, Show your work. BRANLIEST ASAP!! THANK YOU​
4vir4ik [10]

$\cos\theta=\frac{\text{5}}{\text{13}},  \ \sin\theta=\frac{\text{12}}{13}, \ \tan\theta=\frac{\text{12}}{\text{5}}

$\sec\theta=\frac{\text{13}}{\text{5}},\ \csc \theta=\frac{\text{13}}{\text{12}} , \ \cot \theta=\frac{\text{5}}{\text{12}}

Solution:

Given triangle is a right triangle.

Base = 5, Hypotenuse = 13, Height = ?

Height (h) = opposite

<em>In right triangle, square of the hypotenuse is equal to the sum of the squares of the other two sides.</em>

5^2+h^2=13^2

25+h^2=169

h^2=144

Taking square root on both sides.

h = 12

$\cos\theta=\frac{\text{Base}}{\text{Hypotenuse}}

$\cos\theta=\frac{\text{5}}{\text{13}}

$\sin\theta=\frac{\text{Opposite}}{\text{Hypotenuse}}

$\sin\theta=\frac{\text{12}}{13}

$\tan\theta=\frac{\text{Opposite}}{\text{Base}}

$\tan\theta=\frac{\text{12}}{\text{5}}

$\sec\theta=\frac{\text{Hypotenuse}}{\text{Base }}

$\sec\theta=\frac{\text{13}}{\text{5}}

$\csc \theta=\frac{\text{Hypotenuse}}{\text{Opposite }}

$\csc \theta=\frac{\text{13}}{\text{12}}

$\cot \theta=\frac{\text{Base }}{\text{Opposite}}

$\cot \theta=\frac{\text{5}}{\text{12}}

6 0
4 years ago
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