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lisabon 2012 [21]

2 years ago

5

The product of four consecutive odd numbers(all four positive or all four negative)is 62985.find the two possible sets of four n

umber

1 answer:

emmasim [6.3K]2 years ago

8 0

Answer:

Step-by-step explanation:

Let X be the first number.

(X)*(X+2)*(X+4)*(X+6) = 62985

(X^2 + 6X)^2 + 8(X^2 + 6X) = 62985

X = 13, AND X= -19

A. X = 13

(13)(15(17)(19) = 62985

B. X = -19

(-19)(-17)(-15)(-13) = 62985

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ratelena [41]

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tanya purchased 4 hamners for $11.00 each and 7 scewdrivers for $6.65 each write an expresion for the total cost of the tools.th

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3 years ago

F(x) = 3x + 6 please help quickly!!!!!!!

Georgia [21]

Given the function, <em>f(x) = 3x + 6,</em> we can solve for f(a), f(a + h) and $\frac{(f(a + h) - f(a)) }{h}$ by substituting their values into f(x) = 3x + 6. We will have the following:

$\mathbf{f(a) = 3a + 6}\\\\\mathbf{f(a + h) = 3a + 3h + 6}\\\\\mathbf{\frac{(f(a + h) - f(a)) }{h} = 6}$

<em><u>Given:</u></em>

f(x) = 3x + 6

<em>We are told to find:</em>

f(a)
f(a + h), and
$\frac{(f(a + h) - f(a)) }{h}$

1. <em><u>Find f(a):</u></em>

Substitute x = a into f(x) = 3x + 6

f(a) = 3(a) + 6

f(a) = 3a + 6

<em>2. Find f(a + h):</em>

Substitute x = a + h into f(x) = 3x + 6

f(a + h) = 3(a + h) + 6

f(a + h) = 3a + 3h + 6

<em>3. Find </em> $\frac{(f(a + h) - f(a)) }{h}$ <em>:</em>

Plug in the values of f(a + h) and f(a) into $\frac{(f(a + h) - f(a)) }{h}$

Thus:

$\frac{((3a + 3h + 6) - (3a + 6)) }{h}\\\\\frac{(3a + 3h + 6 - 3a - 6) }{h}\\\\$

Add like terms

$\frac{(3a - 3a + 3h + 6 - 6) }{h}\\\\= \frac{3h }{h}\\\\\mathbf{= 3}$

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$\mathbf{f(a) = 3a + 6}\\\\\mathbf{f(a + h) = 3a + 3h + 6}\\\\\mathbf{\frac{(f(a + h) - f(a)) }{h} = 6}$

Learn more here:

brainly.com/question/8161429

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Neko [114]

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