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lisabon 2012 [21]
2 years ago
5

The product of four consecutive odd numbers(all four positive or all four negative)is 62985.find the two possible sets of four n

umber​
Mathematics
1 answer:
emmasim [6.3K]2 years ago
8 0

Answer:

Step-by-step explanation:

Let X be the first number.

(X)*(X+2)*(X+4)*(X+6) = 62985

(X^2 + 6X)^2 + 8(X^2 + 6X) = 62985

X = 13, AND X= -19

A.  X = 13

(13)(15(17)(19) = 62985

B.  X = -19

(-19)(-17)(-15)(-13) = 62985

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ehidna [41]

Answer:

80 - 30(first hour )=50

50-0(2nd hour)=50

50-20=30

30-20=10

10 Is THE ANSWER

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Multi answer inequality! Please help and comment only if you know!
bearhunter [10]

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-8, 0, and -12

Step-by-step explanation:

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3 years ago
A skier has decided that on each trip down a slope, she will do 3 more jumps than before. On her first trip she did 5 jumps. Der
taurus [48]
Since we are already given the amount of jumps from the first trial, and how much it should be increased by on each succeeding trial, we can already solve for the amount of jumps from the first through tenth trials. Starting from 5 and adding 3 each time, we get: 5 8 (11) 14 17 20 23 26 29 32, with 11 being the third trial.

Having been provided 2 different sigma notations, which I assume are choices to the question, we can substitute the initial value to see if it does match the result of the 3rd trial which we obtained by manual adding.

Let us try it below:

Sigma notation 1:

  10
<span>   Σ (2i + 3)
</span>i = 3

@ i = 3

2(3) + 3
12

The first sigma notation does not have the same result, so we move on to the next.

  10
<span>   Σ (3i + 2)
</span><span>i = 3
</span>
When i = 3; <span>3(3) + 2 = 11. (OK)
</span>
Since the 3rd trial is a match, we test it with the other values for the 4th through 10th trials.

When i = 4; <span>3(4) + 2 = 14. (OK)
</span>When i = 5; <span>3(5) + 2 = 17. (OK)
</span>When i = 6; <span>3(6) + 2 = 20. (OK)
</span>When i = 7; 3(7) + 2 = 23. (OK)
When i = 8; <span>3(8) + 2 = 26. (OK)
</span>When i = 9; <span>3(9) + 2 = 29. (OK)
</span>When i = 10; <span>3(10) + 2 = 32. (OK)

Adding the results from her 3rd through 10th trials: </span><span>11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 = 172.
</span>
Therefore, the total jumps she had made from her third to tenth trips is 172.


3 0
3 years ago
Find the ​slope-intercept form of the equation of the line that passes through the point P and makes angle with the positive ​x-
SIZIF [17.4K]

Answer:

The answer is "y= -x+7"

Step-by-step explanation:

If \bold{\theta = 135^{\circ}}

point: p=(2,5)

Formula:

\to m= \tan \theta \\\\\to (y-y_1)= m(x-x_1)

\to m= \tan \ 135^{\circ} =  -1\\\\\to x_1= 2\\\\\to y_1=5

Put the value in the above formula:

\to y- 5 = -1(x-2)\\\\\to y- 5 = -x+2\\\\\to x+y = 5+2\\\\\to x+y=7

\to y= -x+7

3 0
3 years ago
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