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Aneli [31]
3 years ago
12

I need the answer to these questions FAST PLEASE

Mathematics
1 answer:
Yuri [45]3 years ago
7 0

Answer:

\underline{\underline{ \boxed{ans(1)}}}  \:  \boxed{x = 11} \\  \\ \underline{\underline{ \boxed{ans(2)}}}   \:   \boxed{x = 9} \\  \\ \underline{\underline{ \boxed{ans(3)}}}  \:  \boxed{x = 10} \\  \\ \underline{\underline{ \boxed{ans(4)}}}   \: \boxed{x = 6} \\  \\ \underline{\underline{ \boxed{ans(5)}}} \:  \boxed{x = 7} \\  \\ \underline{\underline{ \boxed{ans(6)}}}  \: \boxed{x = 13} \\  \\

Step-by-step explanation:

\underline{\underline{ \boxed{ans(1)}}}   \\  \frac{54}{36}  =  \frac{24}{x + 5} :   \\ (36)(24) = (54)(x + 5) \\ (x + 5) =  \frac{(36)(24)}{(54)}  \\ x = 16 - 5 \\  \boxed{x = 11} \\  \\ \underline{\underline{ \boxed{ans(2)}}}   \\  \frac{(20 + 8)}{20}  =  \frac{(2x + 3)}{15} :   \\ (20)(2x + 3) = (15)(28) \\ (2x + 3) =  \frac{(15)(28)}{(20)}  \\ 2x = 21 - 3 \\2x = 18 \\   \boxed{x = 9} \\  \\ \underline{\underline{ \boxed{ans(3)}}}   \\  \frac{24}{28}  =  \frac{x + 8}{3x  -  9} :   \\ (28)(x + 8) = (24)(3x  - 9) \\ 28x + 224 =  72x- 216  \\ 72x - 28x = 224  + 216 \\ 44x = 440 \\  \boxed{x = 10} \\  \\ \underline{\underline{ \boxed{ans(4)}}}   \\  \frac{39}{4x + 2}  =  \frac{42}{5x    -    2} :   \\ (42)(4x + 2) = (39)(5x  - 2) \\ 168x + 84 =  195x- 78  \\ 195x - 168x = 84  + 78 \\ 27x = 162 \\  \boxed{x = 6} \\  \\ \underline{\underline{ \boxed{ans(5)}}}   \\  \frac{48}{4x + 4}  =  \frac{60}{7x  -  9} :   \\ (60)(4x + 4) = (48)(7x  - 9) \\ 240x + 240 =  336x- 432  \\ 336x - 240x = 240  + 432 \\ 96x = 672 \\  \boxed{x = 7} \\  \\ \underline{\underline{ \boxed{ans(6)}}}   \\  \frac{40}{40 - 5}  =  \frac{3x  -  7}{2x   +   2} :   \\ (40)(2x + 2) = (35)(3x  - 7) \\ 80x + 80 =  105x- 245  \\ 105x - 80x = 80  + 245 \\ 25x = 325 \\  \boxed{x = 13} \\  \\

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write two numbers that when rounded to the greatest place value have an estimated sum of 11000 and an estimated difference of 30
Nookie1986 [14]

Answer:

First, we have rounded numbers A and B, and we know that:

A + B = 11000

A - B = 3000

Now we can solve this system of equations as:

Isolating one variable in one of the equations, i will choose A in the second equation:

A = 3000 + B.

Now we can replace this into the other equation:

3000 + B + B = 11000

2*B = 11000 - 3000 = 8000

B = 8000/2 = 4000

and:

A - 4000 = 3000

A = 3000 + 4000 = 7000.

But remember that our original numbers are not exactly whole numbers, they are rounded up, so we could write them as:

A = 6999.8 (that would be rounded up to 7000)

B = 3999.7 (that would be rounded up to 4000)

The sum is:

A + B = 10999.5 (notice that this would be rounded up to 11000)

A - B =  3000.1 (this would be rounded down to 3000)

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Step-by-step explanation:

31/87(100)

3100/87

35.6%

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