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Amanda [17]
3 years ago
6

What is 31/87 as a percentage? Give your answer rounded to one decimal place.

Mathematics
2 answers:
kicyunya [14]3 years ago
8 0

Answer:

35.6%

Step-by-step explanation:

31/87(100)

3100/87

35.6%

MAXImum [283]3 years ago
8 0

Answer:

35,6%

Step-by-step explanation:

31/87 = 0,35632184

As a percentage: 35,632184%

Rounded to one deciman place: 35,6%

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7 calculators cost £81.90.<br> How much do 11 calculators cost?
Leno4ka [110]

Answer:

128.7

Step-by-step explanation:

81.90 ÷ 7  = 11.7

11.7 x 11 = 128.7

3 0
3 years ago
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I need help with 12.5•10•14 L•W•H
Vera_Pavlovna [14]
<h3>Answer:</h3>

\huge{\boxed{\text{1750 units}^{3}}}

<h3>Explanation:</h3>

\begin{array}{cc}\text{First, multiply 12.5 by 10.}&125*14\\\text{Then, multiply 125 by 14.}&1750\end{array}

8 0
3 years ago
Question 20 not yet answered marked out of 1.00 not flaggedflag question question text luna created a trash can in the shape of
Alex Ar [27]

Consider the triangle with sides a=1.6, b=2.3 and c=1.2 feet. You can use cosine theorem twice to find two unknown angles:

1.

b^2=a^2+c^2-2ac\cos \angle B,\\ (2.3)^2=(1.6)^2+(1.2)^2-2\cdot 1.6\cdot 1.2\cos \angle B,\\ 5.29=2.56+1.44-3.84\cos \angle B,\\ 3.84\cos \angle B=4-5.29=-1.29,\\\cos \angle B=-\dfrac{1.29}{3.84} =-0.336

Then you can conclude that ∠B is obtuse (because \cos \angle B) and m∠B=110°.

2.

c^2=a^2+b^2-2ab\cos \angle C,\\ (1.2)^2=(1.6)^2+(2.3)^2-2\cdot 1.6\cdot 2.3\cos \angle C,\\ 1.44=2.56+5.29-7.36\cos \angle C,\\ 7.36\cos \angle C=7.85-1.44=6.41,\\\cos \angle C=\dfrac{6.41}{7.36} =0.871.

Then you can conclude that ∠C is acute (because \cos \angle C>0) and m∠C=29°.

3. m∠A+m∠B+m∠C=180°, then m∠A=180°-110°-29°=41°.

Answer: m∠A=41° (∠A is opposite to the side a=1.6), m∠B=110° (∠B is opposite to the side b=2.3) and m∠C=29° (∠C is opposite to the side c=1.2)

3 0
3 years ago
Which points can be connected to draw a line of symmetry through this figure?
Alex Ar [27]

The symmetry line is passing through points F and E. Then the correct option is B.

<h3>What is reflectional symmetry?</h3>

Consider a plane. Consider a design or shape on that plane. Now consider an axis.

If we think of that axis as a mirror, and on the opposite side of that axis create the image of the considered shape, then if the shape's image looks exactly like the shape itself, then that shape is called to have reflectional symmetry.

Then the symmetry line is passing through points F and E. Because F and E are the mid-points of AD and BC.

Learn more about symmetry here:

brainly.com/question/7783612

#SPJ1

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2 years ago
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This is you're answer to thia question✉

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