Answer:
I've given you steps already, do it yourself
Answer:
95% confidence interval for the mean number of months is between a lower limit of 6.67 months and an upper limit of 25.73 months.
Step-by-step explanation:
Confidence interval is given as mean +/- margin of error (E)
Data: 5, 15, 12, 22, 27
mean = (5+15+12+22+27)/5 = 81/5 = 16.2 months
sd = sqrt[((5-16.2)^2 + (15-16.2)^2 + (12-16.2)^2 + (22-16.2)^2 + (27-16.2)^2) ÷ 5] = sqrt(58.96) = 7.68 months
n = 5
degree of freedom = n-1 = 5-1 = 4
confidence level (C) = 95% = 0.95
significance level = 1 - C = 1 - 0.95 = 0.05 = 5%
critical value (t) corresponding to 4 degrees of freedom and 5% significance level is 2.776
E = t×sd/√n = 2.776×7.68/√5 = 9.53 months
Lower limit of mean = mean - E = 16.2 - 9.53 = 6.67 months
Upper limit of mean = mean + E = 16.2 + 9.53 = 25.73 months
95% confidence interval is (6.67, 25.73)
6.4 - 2x - 6.63x = 610.5
subtract 6.4 from both sides
-2x -6.63x =604.1
collect like terms
-8.63x = 604.1
divide both sides by -8.63
x= -70
Answer:
The z-score for an income of $2,100 is 1.
Step-by-step explanation:
If X 
N (µ, σ²), then 
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z N (0, 1).
The distribution of these z-variate is known as the standard normal distribution.
Given:
µ = $2,000
σ = $100
<em>x</em> = $2,100
Compute the <em>z</em>-score for the raw score <em>x</em> = 2100 as follows:
Thus, the z-score for an income of $2,100 is 1.
Answer:
x=−5
Step-by-step explanation:
Steps:
Step 1 to 4 : Simplify
Steps 5: Calculating the Least Common Multiple
Steps 6: Calculating Multipliers
The correct answer for this question is x=−5
Answer: x=−5
<em><u>Hope this helps.</u></em>
