![\bf \textit{using the 2nd fundamental theorem of calculus}\\\\ \cfrac{dy}{dx}\displaystyle \left[ \int\limits_{0}^{x}\ cos^{-1}(t)dt \right]\implies cos^{-1}(x) \\\\\\ f'(0.3)\iff cos^{-1}(0.3)\approx 1.26610367277949911126](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Busing%20the%202nd%20fundamental%20theorem%20of%20calculus%7D%5C%5C%5C%5C%0A%5Ccfrac%7Bdy%7D%7Bdx%7D%5Cdisplaystyle%20%5Cleft%5B%20%5Cint%5Climits_%7B0%7D%5E%7Bx%7D%5C%20cos%5E%7B-1%7D%28t%29dt%20%5Cright%5D%5Cimplies%20cos%5E%7B-1%7D%28x%29%0A%5C%5C%5C%5C%5C%5C%0Af%27%280.3%29%5Ciff%20cos%5E%7B-1%7D%280.3%29%5Capprox%201.26610367277949911126)
now.. 0.3 is just a value...we'e assuming Radians for the inverse cosine, so, if you check, make sure your calculator is in Radian mode
Answer:
(in image)
Step-by-step explanation:
sorry it's sloppy i used windows paint to fill it in but if the probability for heads is 2/7 then the probability for tails is 5/7. Multiply the probabilities for each situation to get answers.
Answer:
The answers to the first question are A,C,D
The answer to the second question is YZ=16
Step-by-step explanation:
(1st Question)
Since <K and <M Are equal, and both <L's are equal, KL and ML are congruent (Answer choice) because of the ASA postulate.
You need to create the following equation to find the length of KN and MN 7x-4=5x+12
(Get the "x" variable to one side)
2x-4=12
(Isolate the variable)(Remove the 4)
2x=16
(Divide the 2 by itself to remove it from the x, remember to divide both sides by 2)
x=8 (Answer Choice)
Plug in the x value into each equation
KN= 7(8)-4
KN= 56-4
KN= 52
MN= 5(8)+12
MN= 40+12
MN= 52 (Answer Choice)
MN=KN
(Second Question)
Since XWY(20) is half of XWZ(40), ZWY also equals 20.
This now proves the triangle is congruent by the AAS postulate.
Since the triangles are congruent, if XY = 16, YZ also equals 16.
The number that should go in the box is 6.
3.60
- 0.65
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2. 9 5
