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3 years ago

Write the balanced equation for the reaction of dilute sulfuric acid. H2so4 , with sodium hydroxide

Chemistry

1 answer:

Aleksandr [31]3 years ago

3 0

Answer:

H2SO4 + 2NaOH → Na2SO4 + 2H2O

Explanation:

This question is describing the neutralization reaction between dilute sulfuric acid (H2SO4) and sodium hydroxide (NaOH). These two compounds combine to form sodium salt and water as products (see the chemical equation below).

H2SO4 + NaOH → Na2SO4 + H2O

However, this equation is not BALANCED because the number of atoms of each element are not the same on both sides of the equation. To balance the equation, COEFFICIENTS are used as follows:

H2SO4 + 2NaOH → Na2SO4 + 2H2O

From this equation, the atoms of hydrogen (H), sulphur (S), oxygen (O), sodium (Na) are now equal on both sides, hence, it is said to be BALANCED.

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Which change of state is shown in the model?

Romashka [77]

I believe the change of state shown in the model is deposition.
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3 years ago

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HELP <br> The question is in the picture, I will give 5 stars!

Fynjy0 [20]

The answer is 4.9 moles of salt will be needed to add to 1 kg of water to change the boiling point by 5 °C.

<h3>What is Boiling Point Elevation ?</h3>

Boiling point elevation is the phenomenon that occurs when the boiling point of a liquid (a solvent) is increased when another compound is added, such that the solution has a higher boiling point than the pure solvent.

Boiling point elevation occurs whenever a non-volatile solute is added to a pure solvent.

ΔT = i * Kb * m

where m, Kb and i are the molality of solution, ebullioscopic constant and Van't Hoff factor respectively

The data given in the question is ΔT = 5 °C

mass of solvent = 1 kg

Kb = 0.51 °C/(mol/kg)

Van't Hoff Factor for NaCl is 2

Substituting the values in the above equation

$\rm 5 = \rm\dfrac{2\times0.51\times moles \;of \;salt}{1}$

$\rm moles \;of \;salt = \rm\dfrac{5}{2\times0.51}$

moles of salt = 4.9

Therefore 4.9 moles of salt will be needed to add to 1 kg of water to change the boiling point by 5 °C.

To know more about Boiling point elevation

brainly.com/question/17218953

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2 years ago

How many milliliters of 0.200 M NH4OH are needed to react with 12.0 mL of 0.550 M FeCl3?

trapecia [35]

Answer:

9.9 ml of 0.200M NH₄OH(aq)

Explanation:

3NH₄OH(Iaq) + FeCl₃(aq) => NH₄Cl(aq) + Fe(OH)₃(s)

?ml of 0.200M NH₄OH(aq) reacts completely with 12ml of 0.550M FeCl₃(aq)

1 x Molarity NH₄OH x Volume Am-OH Solution(L) = 2 x Molarity FeCl₃ x Volume FeCl₃ Solution

1(0.200M)(Vol Am-OH Soln) = 3(0.550M)(0.012L)

=> Vol Am-OH Soln = 3(0.550M)(0.012L)/1(0.200M) = 0.0099 Liter = 9.9 milliliters

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3 years ago

What happens to particles when in a substance with a a low temperature

Finger [1]

Temperature affects the motion and the liquid. As the temperature of the solid, liquid or gas increases, the particles move more rapidly. As the temperature falls, Cabato slow down. If a liquid is called significantly, it forms a solid

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3 years ago

Which of the following is a covalent bond? A NaCl B K2O C H2O D MgO

Black_prince [1.1K]

Answer:

$H_2O$

Explanation: Research has proven that ;

Water is a Polar Covalent Molecule

It consists of 2 Hydrogen molecules bonded to one Oxygen molecule and the two hydrogen atoms are not evenly distributed around the oxygen atom.

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3 years ago