Answer:
-0.044 V
Explanation:
The overall electrode potential is usually estimated by subtracting the potential of the reference electrode from the potential of the system in question. In the given problem, the standard electrode potential of silver-silver chloride with respect to the standard hydrogen electrode is +0.197 V. In addition, the potential of the calomel reference electrode with respect to the standard hydrogen electrode is +0.241 V. Using the data above, the potential of with respect to silver-silver chloride is equivalent to 0.197-0.241 = -0.044 V.
C: 4 H on the left and right, 4 O on both sides making it balanced
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Answer:
- According to the law <br> Mass of reactants = mass of product, here <br> `underset(10 g)(CaCO_(3))rarr underset(4.4 g)(CO_(2))+underset(x)(CaO)` <br> Hence, x = 10 g - 4.4 g = 5.6 g <br> Which is mass of CaO.d
- In the first compound <br> Hydrogen = 5.93 % <br> Oxygen = `(100-5.93)% = 94.07 %` <br> In the second compound <br> Hydrogen = 11.2 % <br> Oxygen `= (100-11.2)%=88.8%` <br> In the first compound the number of parts by mass of oxygen that combine with one part by mass of hydrogen `=(94.07)/(5.93)=15.86` parts ...
- (The ratio of Cu combining with fixed weight of oxygen in black and red oxide is 1 : 2 respectively. Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.) {Check something more in the above attachment!}
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Explanation:
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