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3 years ago

7

PLZ HURRY i need this for test if you have the answers for all questions plz put the test is for plato algebra A1 unit3 post tes

t thx

1 answer:

elena-14-01-66 [18.8K]3 years ago

7 0

Explanation is in the file

tinyurl.com/wpazsebu

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A coin and a die is rolled. What is the probability of a head and a 3?

saw5 [17]

Answer:

1/6

Step-by-step explanation:

The probability of <em>only</em> a heads on a coin is 1/2, and the probability of <em>only</em> a 3 on a die is 1/6. Multiply them together, and you get 1/6.

6 0

3 years ago

There are 3 red and 8 green balls in a bag. If you randomly choose balls one at a time, with replacement, what is the probabilit

Kaylis [27]

So, the total number of balls is 11. We want to pick 2 red balls and 1 green ball. WLOG (since order doesnt matter here), we can say he picks red, green, red. That means on his first pick, he has a $\frac{3}{11}$ chance of picking the red ball, and he places it back in the bag. The probability of picking a green ball is $\frac{8}{11}$ , and then he places the ball back in the bag. The probability of picking the last red ball is the same as the last red ball example, and we simply multiply the probabilities together as per the multiplication rule to get:

$\frac{3}{11}\frac{3}{11}\frac{8}{11}=\frac{3*3*8}{11^3}=\frac{72}{1331}$

Now, without replacement the order does matter. He picks a red ball, a red ball then a green ball. The probability of picking the first red ball is $\frac{2}{11}$ , and the probability of picking the second red ball is $\frac{1}{10}$ and the probability of picking the green ball is $\frac{1}{9}$ . We want to multiply thm again, as per the multiplication rule like the last problem.

$\frac{2}{11}*\frac{1}{10}*\frac{1}{9}=\frac{1}{11*5*9}=\frac{1}{495}$

5 0

3 years ago

What is 8/9 of 925935??????????????????<br> ⇒Who wants to talk :)<br> ❤️

just olya [345]

Answer:

823,053.33333

Step-by-step explanation:

plz follow me

6 0

3 years ago

Susan started her homework at 1{:}59\text { p.M.}1:59 p.M.1, colon, 59, start text, space, p, point, m, point, end text and fini

inn [45]

Answer:

Step-by-step explanation:

Susan started her homework at = 1:59 pm

She took time = 96 mins

Time at which she had volleyball practice = 4:00 pm

So, time between her starting of homework and starting of volleyball is given by

1:59 pm to 4:00 pm = 2 hrs and 1 mins

2 hr 1 min = 120 mins + 1 min = 121 mins

But she took 96 mins to do her homework, so

Out of 121 mins, 96 mins she took for homework

Remaining time = 121 mins - 96 mins = 25 mins

Therefore, time Susan had between finishing her homework and the beginning of volleyball practice is 25 mins

7 0

3 years ago

HELP PLEASE THANKS!!!!!

STALIN [3.7K]

Multiply 11 yards by 7 yeards and you will get ur answrr

4 0

2 years ago