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2 years ago

Ally sliced 32kg of watermelon for a party. She divided the watermelon slices equally between 8 large bowls.

Mathematics

2 answers:

adelina 88 [10]2 years ago

7 0

Answer:

4000g

Step-by-step explanation:

32kg=32000g

32000/8 bowls=

4000g

iVinArrow [24]2 years ago

4 0

Answer: 4000 Grams

(Edited! I was wrong!)

Step-by-step explanation:

32 divided by 8 is 4. Add the units, and youre done! (x1000 bc 1000 kg are in a gram)

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Please help!! I have 10 minutes left!!

Lelu [443]

1. Answer:

30 is your frequency

Step-by-step explanation:

Frequency in this case would be the number of winners. So to find the frequency we would need to add up the total number of winners in the histogram.

So, 0 + 2 + 5 + 6 + 8 + 5 + 4 = 30

2. Answer:

6 (you already put that)

The median can be found in the 50-59 bin or interval.

5 0

2 years ago

Q5: The probability that event A occurs is 5/7 and the probability that event B occurs is 2/3 . If A and B are independent event

bekas [8.4K]

Answer:

$P(A \cap B)$

And we can use the following formula:

$P(A \cap B)= P(A)* P(B)$

And replacing the info we got:

$P(A \cap B) = \frac{5}{7} \frac{2}{3}= \frac{10}{21}=0.476$

Step-by-step explanation:

We define two events for this case A and B. And we know the probability for each individual event given by the problem:

$p(A) = \frac{5}{7}$

$p(B) = \frac{2}{3}$

And we want to find the probability that A and B both occurs if A and B are independent events, who menas the following conditions:

$P(A|B) = P(A)$

$P(B|A) = P(B)$

And for this special case we want to find this probability:

$P(A \cap B)$

And we can use the following formula:

$P(A \cap B)= P(A)* P(B)$

And replacing the info we got:

$P(A \cap B) = \frac{5}{7} \frac{2}{3}= \frac{10}{21}=0.476$

7 0

2 years ago

If the distance traveled is (4s3 - 6s² + 4s + 14) miles and the rate is (s + 1) mph, write an expression, in hours, for the time

BartSMP [9]

The equation for time is URM:

$time = \frac{distance}{speed \: (rate)}$

$t(s) = \frac{4s {}^{3} - 6s {}^{2} + 4s + 14}{s + 1} = \frac{2(s + 1)(2s {}^{2} - 5s + 7) }{s + 1} \\ t(s) = 2(2s {}^{2} - 5s + 7) \\ t(s) = 4s {}^{2} - 10s + 14$

3 0

9 months ago

Can somebody explain to me how to solve multiple linear equations???

Kryger [21]

Answer:

so what are the equations you're having trouble with?

4 0

2 years ago

Flying against the wind, an airplane travels 7520 kilometers in 8 hours. Flying with the wind, the same plane travels 6500 kilom

bezimeni [28]

Answer:

Rate of plane in still air = 1120 km/h

Rate of wind = 180 km/h

Step-by-step explanation:

Let the rate (speed) of the plane in still air = u km/h

Let the rate (speed) of the wind = v km/h

Formula for speed is:

$Speed = \dfrac{Distance}{Time}$

Given that against the wind, airplane travels 7520 km in 8 hours.

The speed against the wind will be slower so,

Against the wind, speed = (u -v ) km/h

Using above formula:

$(u-v) = \dfrac{7520}{8} km/h\\(u-v) = 940 km/h ..... (1)$

Given that with the wind, airplane travels 6500 km in 5 hours.

The speed with the wind will be faster so,

With the wind, speed = (u +v ) km/h

Using above formula:

$(u+v) = \dfrac{6520}{5} km/h\\(u+v) = 1300 km/h ..... (2)$

Adding (1) and (2) to solve for u and v:

$2u = 2240\\\Rightarrow u = 1120\ km/h$

Putting u in (1):

$1120-u=940\\\Rightarrow u = 180\ km/h$

So, the answers are:

Rate of plane in still air = 1120 km/h

Rate of wind = 180 km/h

6 0

2 years ago