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Digiron [165]
2 years ago
5

Find the value of x number on top is 6 and other is 9

Mathematics
1 answer:
faltersainse [42]2 years ago
5 0

Answer:

x = - 12, 3

Step-by-step explanation:

By tangent secant theorem:

x(x + 9) =  {6}^{2}  \\  \\  {x}^{2}  + 9x = 36 \\  \\  {x}^{2}  + 9x - 36 = 0 \\  \\  {x}^{2}  + 12x - 3x - 36 = 0 \\  \\ x(x + 12) - 3(x + 12) = 0 \\  \\ (x + 12)(x - 3) = 0 \\  \\ x + 12 = 0, \:  \: x - 3 = 0 \\  \\ x =  - 12, \:  \: x = 3 \\  \\

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Carol noticed that 7/10 of the children playing soccer were girls. Which statement could be correct?
Maslowich
<span>Carol noticed that 7/10 of the children playing soccer were girls. Which statement could be correct?
A. There were 28 girls and 12 boys playing soccer.
28 : x% = 40 (the total number of children) : 100%
40x = 28 * 100
40x = 2800
x = 2800 / 40
x = 70%
There were 70% of girls in the class.
70 / 100 = 0.7
7/ 10 = 0.7
This is why A is the correct answer.

</span>
7 0
3 years ago
A cone has a base area of 420mm and height of 180mm. What is the volume of the cone.
luda_lava [24]

Cone Volume = PI * radius^2 * height / 3, which can br rewritten as

Cone Volume = base area * height / 3

Cone Volume = 420mm * 60

Cone Volume = 25,200 cubic mm

3 0
3 years ago
What is the center of dilation
Goryan [66]

Answer:

Step-by-step explanation:a

5 0
3 years ago
Math help!<br> (check the attachment)
Evgesh-ka [11]
(x-30)+(x+76)=180
x-30+x+76=180
2x+46=180
2x=134
x=67
67-30=37
67+76=143
<1=37, <2=143
5 0
2 years ago
Read 2 more answers
At the beginning of year 1, Josie invests $400 at an annual compound interest
zvonat [6]

Answer:

The explicit formula that can be used is A=\$400(1.05)^{2}

The account's balance at the beginning of year 3 is A=\$441  

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=2\ years\\ P=\$400\\ r=0.05\\n=1  

substitute in the formula above  

A=\$400(1+\frac{0.05}{1})^{1*2}  

A=\$400(1.05)^{2}

A=\$441  

3 0
3 years ago
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