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3 years ago

Help me with this pls

Mathematics

1 answer:

koban [17]3 years ago

5 0

Answer:

The answer should be C because the airplane ascends and descends within bla3 minutes

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A circle is centered at M (0,0). The point B (-4, square root of 5) is on the circle. Where does the point A (5,-1) lie?

Norma-Jean [14]

Answer: outside the circle

Step-by-step explanation: use pythagorean theorem to check radius of circle using the given points on a circle and see if the radius of the second point matches up using pythagorean theorem. use a graphing calculator to double check.

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4 years ago

The angles in a triangle are in the ratio 1 : 2 : 3.

vekshin1

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yes

Step-by-step explanation:

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3 years ago

1. Design your own real-world scenario in which the solution requires the Pythagorean Theorem. Use complete sentences to describ

tigry1 [53]

Answer:

this is not maths

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2 years ago

Find the differential of each function. (a) y = tan( 5t ) dy = Correct: Your answer is correct. (b) y = 5 − v2 5 + v2

Trava [24]

Answer:

$(a)$ $dy = 5sec^2(5t) \ dt$

$(a) \ dy = \frac{-20v}{(5+v^2)^2} \ dt$

Step-by-step explanation:

Given;

(a) y = tan(5t)

$(b) \ y = \frac{5-v^2}{5+v^2}$

Solving for (a)

y = tan(5t)

let u = 5t

⇒y = tan(u)

du/dt = 5

dy/du = sec²u

$\frac{dy}{dt} =\frac{dy}{du} *\frac{du}{dt} \\\\\frac{dy}{dt} = sec^2(u)*5\\\\\frac{dy}{dt} = 5sec^2(u)\\\\\frac{dy}{dt} = 5sec^2(5t)$

$dy = 5sec^2(5t) \ dt$

Solving for b;

let u = 5 - v²

du/dv = -2v

let v = 5+ v²

dv/du = 2v

$\frac{dy}{dv} = \frac{vdu - udv}{v^2} \\\\\frac{dy}{dv} = \frac{-2v(5+v^2) - 2v(5-v^2)}{(5+v^2)^2}\\\\\frac{dy}{dv} = \frac{-10v-2v^3-10v+2v^3}{(5+v^2)^2}\\\\$

$\frac{dy}{dv} = \frac{-10v-10v}{(5+v^2)^2}\\\\\frac{dy}{dv} = \frac{-20v}{(5+v^2)^2}\\\\dy = \frac{-20v}{(5+v^2)^2} dt$

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3 years ago

Using a calculator to increase 355 by 12% equals ??(. )

Natasha2012 [34]

Answer:

$355 + \frac{12}{100 } \times 355 \\ = 397.6$

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3 years ago

Read 2 more answers