<img src="https://tex.z-dn.net/?f=%28x%5E%7B2%7D%20%2B1%29%28x%5E%7B2%7D%20-1%29%5E%7B6%7D" id="TexFormula1" title="(x^{2} +1)(x

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inessss [21]

3 years ago

^{2} -1)^{6}" alt="(x^{2} +1)(x^{2} -1)^{6}" align="absmiddle" class="latex-formula">

Mathematics

2 answers:

Ann [662]3 years ago

8 0

X^4 - 5x^12 + 9x^10 - 5x^8 - 5x^6 + 9x^4 - 5x^2 + 1

Nady [450]3 years ago

5 0

Answer:

(x²+1)(x²-1)⁶ = x¹⁴-5x¹²+9x¹⁰-5x⁸-5x⁶+9x⁴-5x²+1

Step-by-step explanation:

Pascal triangle 6th row for (a + (-b))⁶; ... for (x²-1)⁶

a⁶+6a⁵(b)¹+15a⁴(b)²+20a³(b)³+15a²(b)⁴+6a(b)⁵+1*(b)⁶ .. a=x² b = -1

= x¹²+6x¹⁰(-1)¹+15x⁸(-1)²+20x⁶(-1)³+15x⁴(-1)⁴+6x²(-1)⁵+1*(-1)⁶

= x¹²-6x¹⁰+15x⁸-20x⁶+15x⁴-6x²+1

(x²+1)(x²-1)⁶ = (x²+1)(x¹²-6x¹⁰+15x⁸-20x⁶+15x⁴-6x²+1)

= x¹⁴-5x¹²+9x¹⁰-5x⁸-5x⁶+9x⁴-5x²+1

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Given:

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